zoukankan      html  css  js  c++  java
  • 5.经典例题


    #1.查询工资最低的员工信息:last_name,salsry
    ①SELECT MIN(salary)
    FROM employees
    ②SELECT last_name,salary
    FROM employees
    WHERE salary=(
    SELECT MIN(salary)
    FROM employees
    );

    #2.查询平均工资最低的部门信息
    ①SELECT DISTINCT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary)
    LIMIT 1;
    ②SELECT *
    FROM departments
    WHERE department_id=(
    SELECT DISTINCT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary)
    LIMIT 1
    );
    #3.查询平均工资最低的部门信息和该部门的平均工资
    ①SELECT DISTINCT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary)
    LIMIT 1;
    ②SELECT DISTINCT department_id,AVG(salary)
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary)
    LIMIT 1

    ③SELECT d.*,ag
    FROM departments d
    JOIN (
    SELECT DISTINCT department_id,AVG(salary) ag
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary)
    LIMIT 1
    )ag_dep
    ON d.department_id= ag_dep.department_id

    #4.查询平均工资高于公司平均工资的部门有哪些
    ①SELECT AVG(salary)
    FROM employees
    ②SELECT AVG(salary) ag,department_id
    FROM employees
    GROUP BY department_id
    HAVING ag>(
    SELECT AVG(salary)
    FROM employees
    )

    #5.查询出公司中所有manager的详细信息
    SELECT e.*
    FROM employees e
    WHERE e.employee_id IN( #或者=any(
    SELECT DISTINCT manager_id
    FROM employees
    )
    #6.各部门中 最高工资中的最低的那个部门的 最低工资
    ①SELECT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY MAX(salary)
    LIMIT 1

    SELECT MIN(salary)
    FROM employees
    WHERE department_id = (
    SELECT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY MAX(salary)
    LIMIT 1
    );

    #7.查询平均工资最高的部门的 manager的详细信息:last_name,department_id,email,salary
    ①SELECT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary) DESC
    LIMIT 1
    ② SELECT last_name,d.department_id,email,salary
    FROM employees e
    INNER JOIN departments d
    ON d.manager_id = e.employee_id
    WHERE d.department_id = (
    SELECT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary) DESC
    LIMIT 1
    );

  • 相关阅读:
    C# 中文件路径的操作
    字符串模式匹配KMP算法
    SLG游戏关卡设计
    android 源码包结构分析
    NIO的理解
    显示单位
    多线程时控制并发数据库操作的思路
    使用异常机制的建议
    合理的使用索引。《Map的使用》
    android源码的下载方法Windows
  • 原文地址:https://www.cnblogs.com/sun1997/p/12572188.html
Copyright © 2011-2022 走看看