Populating Next Right Pointers in Each Node II

Populating Next Right Pointers in Each Node II 

问题：

Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL.

Initially, all next pointers are set to NULL.

Note:

• You may only use constant extra space.
• You may assume that it is a perfect binary tree (ie, all leaves are at the same level, and every parent has two children).

For example,
Given the following perfect binary tree,

思路：

　　队列

我的代码：

public class Solution {
    public void connect(TreeLinkNode root) {
        if(root == null)    return;
        Queue<TreeLinkNode> queue = new LinkedList<TreeLinkNode>();
        queue.offer(root);
        while(!queue.isEmpty())
        {
            int size = queue.size();
            TreeLinkNode head = queue.poll();
            if(head.left != null) queue.offer(head.left);
            if(head.right != null) queue.offer(head.right);
            for(int i = 1; i < size; i++)
            {
                TreeLinkNode cur = queue.poll();
                if(cur.left != null) queue.offer(cur.left);
                if(cur.right != null)   queue.offer(cur.right);
                head.next = cur;
                head = cur;
            }
            head.next = null;
        }
        
        return;
    }
}