1、单行写一个评级组件
"★★★★★☆☆☆☆☆".slice(5 - rate, 10 - rate);定义一个变量rate是1到5的值，然后执行上面代码，看图
才发现插件什么的都弱爆了
2、如何装逼用代码骂别人SB
(!(~+[])+{})[--[~+""][+[]]*[~+[]] + ~~!+[]]+({}+[])[[~!+[]]*~+[]]
了解为什么请移步：一行能装逼的JavaScript代码
3、如何用代码优雅的证明自己NB
这个牛逼了
console.log(([][[]]+[])[+!![]]+([]+{})[!+[]+!![]])
4、JavaScript 错误处理的方式的正确姿势
，舅服你
try {
something
} catch (e) {
window.location.href =
"http://stackoverflow.com/search?q=[js]+" +
e.message;
}
5、从一行代码里面学点JavaScript
[].forEach.call($$("*"),function(a){
a.style.outline="1px solid #"+(~~(Math.random()*(1<<24))).toString(16)
})
翻译成正常语言就是这样的
Array.prototype.forEach.call(document.querySelectorAll('*'),
dom => dom.style.outline = `1px solid #${parseInt(Math.random() *
Math.pow(2,24)).toString(16)}`)
接下来在浏览器控制看看：something magic happens
具体分析请参见这篇文章：从一行代码里面学点JavaScript
6、论如何优雅的取随机字符串
Math.random().toString(16).substring(2)
Math.random().toString(36).substring(2)
7、(10)["toString"]() === "10"
解析请移步：js奇淫技巧1
8、匿名函数自执行
这么多写法你选择哪一种？我选择死亡。
( function() {}() );
( function() {} )();
[ function() {}() ];
~ function() {}();
! function() {}();
+ function() {}();
- function() {}();
delete function() {}();
typeof function() {}();
void function() {}();
new function() {}();
new function() {};
var f = function() {}();
1, function() {}();
1 ^ function() {}();
1 > function() {}();
// ...
9、另外一种undefined
从来不需要声明一个变量的值是undefined，因为JavaScript会自动把一个未赋值的变量置为undefined。所有如果你在代码里这么写，会被鄙视的
var data = undefined;
但是如果你就是强迫症发作，一定要再声明一个暂时没有值的变量的时候赋上一个undefined。那你可以考虑这么做：
var data = void 0; // undefined
void在JavaScript中是一个操作符，对传入的操作不执行并且返回undefined。void后面可以跟()来用，例如void(0)，看起来是不是很熟悉？没错，在HTML里阻止带href的默认点击操作时，都喜欢把href写成javascript:void(0)，实际上也是依靠void操作不执行的意思。
当然，除了出于装逼的原因外，实际用途上不太赞成使用void，因为void的出现是为了兼容早起ECMAScript标准中没有undefined属性。void 0的写法让代码晦涩难懂。
10、论如何优雅的取整
var a = ~~2.33
var b= 2.33 | 0
var c= 2.33 >> 0
11、如何优雅的实现金钱格式化：1234567890 --> 1,234,567,890
用正则魔法实现：
var test1 = '1234567890'
var format = test1.replace(/B(?=(d{3})+(?!d))/g, ',')
console.log(format) // 1,234,567,890
非正则的优雅实现：
function formatCash(str) {
return str.split('').reverse().reduce((prev, next, index) => {
return ((index % 3) ? next : (next + ',')) + prev
})
}
console.log(formatCash('1234567890')) // 1,234,567,890
12、这个我服，还有这个你很机智
我服
while (1) {
alert('牛逼你把我关了啊')
}
你很机智，好一个障眼法
清除缓存： <a href="javascript:alert('清除成功');">清除缓存</a>
13、逗号运算符
var a = 0;
var b = ( a++, 99 );
console.log(a); // 1
console.log(b); // 99
14、论如何最佳的让两个整数交换数值
常规办法：
var a=1,b=2;
a += b;
b = a - b;
a -= b;
缺点也很明显，整型数据溢出，对于32位字符最大表示数字是2147483647，如果是2147483645和2147483646交换就失败了。
黑科技办法：
a ^= b;
b ^= a;
a ^= b;
哈哈
，看不懂的童鞋建议去补习一下C语言的位操作，我就不去复习了，以前学嵌入式时候学的位操作都忘了
15、实现标准JSON的深拷贝
var a = {
a: 1,
b: { c: 1, d: 2 }
}
var b=JSON.parse(JSON.stringify(a))
不考虑IE的情况下，标准JSON格式的对象蛮实用，不过对于undefined和function的会忽略掉。
16、不用Number、parseInt和parseFloat和方法把"1"字符串转换成数字
哈哈，不准用强制类型转换，那么就想到了强大了隐式转换
var a =1
+a
17、如何装逼的写出"hello world!"
滚动条很长哦
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居然能运行，牛逼的隐式转换
18、parseInt(0.0000008) === 8
19、++[[]][+[]]+[+[]] == 10
强大的隐式转换，23333
20、0.1 + 0.2 == 0.3
0.1 +0.2 == 0.3 竟然是不成立的。。。。所以这就是为什么数据库存储对于货币的最小单位都是分。
简单说，0.1和0.2的二进制浮点表示都不是精确的，所以相加后不是0.3，接近（不等于）0.30000000000000004。
所以，比较数字时，应该有个宽容值。ES6中这个宽容值被预定义了：Number.EPSILON。
21、最短的代码实现数组去重
[...new Set([1, "1", 2, 1, 1, 3])]
前不久面试阿里就问了这道题，哈哈，所以也写上一下
22、用最短的代码实现一个长度为m(6)且值都n(8)的数组
Array(6).fill(8)
这个够短了吧，好像是当初哪里看到的一个面试题，就自己想到了ES6的一些API
23、短路表达式
条件判断
var a = b && 1
// 相当于
if (b) {
a = 1
} else {
a = b
}
var a = b || 1
// 相当于
if (b) {
a = b
} else {
a = 1
}
24、JavaScript版迷宫
逃出迷宫，2333
25、取出一个数组中的最大值和最小值
var numbers = [5, 458 , 120 , -215 , 228 , 400 , 122205, -85411];
var maxInNumbers = Math.max.apply(Math, numbers);
var minInNumbers = Math.min.apply(Math, numbers);
26、将argruments对象转换成数组
var argArray = Array.prototype.slice.call(arguments);
或者ES6：
var argArray = Array.from(arguments)
27、javascript高逼格之Function构造函数
很多JavaScript教程都告诉我们，不要直接用内置对象的构造函数来创建基本变量，例如var arr = new Array(2); 的写法就应该用var arr = [1, 2];的写法来取代。
但是，Function构造函数（注意是大写的Function）有点特别。Function构造函数接受的参数中，第一个是要传入的参数名，第二个是函数内的代码（用字符串来表示）。
var f = new Function('a', 'alert(a)');
f('jawil'); // 将会弹出窗口显示jawil
这种方式可以根据传入字符串内容来创建一个函数 是不是高大上？！
28、从一个数组中找到一个数，O(n)的算法，找不到就返回 null。
正常的版本:
function find (x, y) {
for ( let i = 0; i < x.length; i++ ) {
if ( x[i] == y ) return i;
}
return null;
}
let arr = [0,1,2,3,4,5]
console.log(find(arr, 2))
console.log(find(arr, 8))
结果到了函数式成了下面这个样子（好像上面的那些代码在下面若影若现，不过又有点不太一样，为了消掉if语言，让其看上去更像一个表达式，动用了 ? 号表达式）：
//函数式的版本
const find = ( f => f(f) ) ( f =>
(next => (x, y, i = 0) =>
( i >= x.length) ? null :
( x[i] == y ) ? i :
next(x, y, i+1))((...args) =>
(f(f))(...args)))
let arr = [0,1,2,3,4,5]
console.log(find(arr, 2))
console.log(find(arr, 8))