java多线程计算机流水线模型

/*设计一个生产电脑和搬运电脑类，要求每生产出一台电脑就搬走一台电脑。
*没有生产出新的电脑，则搬运工要等待新电脑产出；
*如果生产出的电脑没有搬走，则要等待电脑搬走之后再生产，并统计出生产的电脑数量。 
*/
package Java多线程_01;

class Resource_01{
	private Computer computer;
	public synchronized void make() throws Exception{
		if(this.computer != null) {
			super.wait();
		}
		Thread.sleep(100);
		this.computer = new Computer("惠普v1000", 11000);
		System.out.println("【生产电脑】" + this.computer);
		super.notifyAll();
	}
	public synchronized void get() throws Exception{
		if(this.computer == null) {
			super.wait();
		}
		Thread.sleep(10);
		System.out.println("【取走电脑】"+this.computer);
		this.computer = null;
		super.notifyAll();
	}
}

class Computer{
	private static int count = 0;
	private String name;
	private double price;
	public Computer(String name, double price) {
		this.name = name;
		this.price = price;
		count++;
	}
	public String toString() {
		return "【第"+count+"台电脑】"+"电脑品牌："+this.name+"、价值："+this.price;
	}
}

class Producer_01 implements Runnable{
	private Resource_01 resource;
	public Producer_01(Resource_01 resource) {
		this.resource = resource;
	}
	public void run() {
		for(int x=0;x<50;x++) {
			try {
				this.resource.make();
			}catch(Exception e) {
				e.printStackTrace();
			}
		}
	}
}

class Consumer_01 implements Runnable{
	private Resource_01 resource;
	public Consumer_01(Resource_01 resource) {
		this.resource = resource;
	}
	public void run() {
		for(int x=0;x<50;x++) {
			try {
				this.resource.get();
			}catch (Exception e) {
				e.printStackTrace();
			}
		}
	}
}

public class homework_02 {
	public static void main(String[] args) {
		Resource_01 resource = new Resource_01();
		new Thread(new Producer_01(resource)).start();
		new Thread(new Consumer_01(resource)).start();
	}
}