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  • leetcode: unique paths II

    Follow up for "Unique Paths":

    Now consider if some obstacles are added to the grids. How many unique paths would there be?

    An obstacle and empty space is marked as 1 and 0 respectively in the grid.

    For example,

    There is one obstacle in the middle of a 3x3 grid as illustrated below.

    [
      [0,0,0],
      [0,1,0],
      [0,0,0]
    ]
    

    The total number of unique paths is 2.

    Note: m and n will be at most 100.

    public class Solution {
        public int uniquePathsWithObstacles(int[][] obstacleGrid) {
            
            if(obstacleGrid == null || obstacleGrid.length == 0 || obstacleGrid[0].length == 0){
                return 0;
            }
            
            int m = obstacleGrid.length;
            int n = obstacleGrid[0].length;
            
            int[][] dp = new int[m][n];
            
            for(int i = 0; i < n; i++){
                if(obstacleGrid[0][i] == 0){
                    dp[0][i] = 1;
                }else{
                    break;
                }
            }
            
            for(int j = 0; j < m; j++){
                if(obstacleGrid[j][0] == 0){
                    dp[j][0] = 1;
                }else{
                    break;
                }
            }
            
            for(int i = 1; i < m; i++ ){
                for(int j = 1; j < n; j++){
                    if(obstacleGrid[i][j] == 1){
                        dp[i][j] = 0;
                    }else{
                        dp[i][j] = dp[i - 1][j] + dp[i][j - 1];
                    }
                }
            }
            
            return dp[m - 1][n - 1];
        }
    }
    

      

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  • 原文地址:https://www.cnblogs.com/superzhaochao/p/6473591.html
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