The gray code is a binary numeral system where two successive values differ in only one bit.
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return [0,1,3,2]
. Its gray code sequence is:
00 - 0 01 - 1 11 - 3 10 - 2
Note:
For a given n, a gray code sequence is not uniquely defined.
For example, [0,2,3,1]
is also a valid gray code sequence according to the above definition.
For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
class Solution { public: inline int changeBit(int value,int i){ unsigned int b=1; i--; b=b<<i; if((b&value)>0){ return value&(~b); } else{ return value|b; } return value; } inline int differ(int a,int b){ a=a^b; int i=1; for(;;){ if(a&1){ return i; } else{ i++; a=a>>1; } } } vector<int> grayCode(int n) { // Start typing your C/C++ solution below // DO NOT write int main() function vector<int>ret; if(n<0){ return ret; } else if(n==0){ ret.push_back(0); return ret; } int length=1; int b=n; for(;b>0;b--)length*=2; int* bits=new int[length]; memset(bits,0,length*sizeof(int)/sizeof(char)); ret.push_back(0); ret.push_back(1); int current=1; if(n==1){ delete bits; return ret; } bits[0]=1; bits[current]++; bool forward=true; int i=1; for(;;){ /*for(int j=0;j<ret.size();j++){ cout<<ret[j]<<" "; } cout<<endl;*/ if(forward){ int v=changeBit(ret[current],i); current++; ret.push_back(v); if(bits[ret[current]]){ forward=false; } else{ forward=true; i=1; if(current==length-1) break; } bits[ret[current]]++; } else{ bits[ret[current]]--; current--; i=differ(ret[current],ret[current+1]); ret.pop_back(); if(i==n){ forward=false; } else { forward=true; i++; } } } delete bits; return ret; } };