Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
ListNode* root;
ListNode* tail;
if(l1!=NULL&&l2!=NULL){
if(l1->val>l2->val){
root=l2;
tail=root;
l2=l2->next;
}
else{
root=l1;
tail=root;
l1=l1->next;
}
while(l1!=NULL&&l2!=NULL){
if(l1->val>l2->val){
tail->next=l2;
tail=tail->next;
l2=l2->next;
}
else{
tail->next=l1;
tail=tail->next;
l1=l1->next;
}
}
if(l1!=NULL)tail->next=l1;
if(l2!=NULL)tail->next=l2;
return root;
}
else{
if(l2==NULL)return l1;
else return l2;
}
}
};