Given a collection of integers that might contain duplicates, S, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For example,
If S = [1,2,2]
, a solution is:
[ [2], [1], [1,2,2], [2,2], [1,2], [] ]
普通遍历
class Solution { public: vector<vector<int> > subsetsWithDup(vector<int> &S) { // Start typing your C/C++ solution below // DO NOT write int main() function set<vector<int> > res; vector<int> one; vector<int> oneone; int i; vector<int> check; for(i=0;i<S.size();i++)check.push_back(0); i=0; while(true){ if(check[i]==2){ i--; if(i<0)break; one.pop_back(); } else{ if(check[i]==1){ one.push_back(S[i]); } check[i]++; i++; if(i==S.size()){ oneone=one; sort(oneone.begin(),oneone.end()); res.insert(oneone); i--; } else{ check[i]=0; } } } set<vector<int> >::iterator it; vector<vector<int> > ret; for(it=res.begin();it!=res.end();it++){ ret.push_back(*it); } return ret; } };