两个辅助指针变量截取字符串

如题：有一个字符串符合以下特征(”abcdef,acccd,eeee,aaaa,e3eeeee,sssss,";)

思路：用一个二维数组来存储截取后的字符串，以'  ，'作为分隔符，截取完一个字符串后，更新当前的位置。直到'    '.

代码：

#include <stdlib.h>
#include <string.h>
#include <stdio.h>
int splitString(const char *buf1, char c, char buf2[10][30], int *count)
{
    char *p=NULL, *pTmp = NULL;
    int    tmpcount = 0;
    //1. p和ptmp初始化
    p = buf1;
    pTmp = buf1;
    do
    {
        //2.检索符合条件的位置p后移形成差值挖字符串
        p = strchr(p, c);
        if (p != NULL)
        {
            if (p-pTmp > 0)
            {
                strncpy(buf2[tmpcount], pTmp,  p-pTmp);
                buf2[tmpcount][p-pTmp]  = '';  //把第一行数据变成 C风格字符串
                tmpcount ++;
                //3.重新让p和ptmp达到下一次检索的条件
                pTmp = p = p + 1;
            }
        }
        else
        {
            break;
        }
    } while (*p!='');

    *count = tmpcount;
    return 0;
}
int main(int argc,char *argv)
{
    int ret = 0, i = 0;
    char *p1 = "abcdef,acccd,eeee,aaaa,e3eeeee,sssss,";
    char cTem= ',';
    int nCount;
    char myArray[10][30];

    ret = splitString(p1, cTem, myArray, &nCount);

    if (ret != 0)
    {
        printf("fucn spitString() err: %d 
", ret);
        return ret;
    }
    for (i=0; i<nCount; i++ )
    {
        printf("%s 
", myArray[i]);
    }
    printf("Split complete
");
    return ;
}