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  • C# json

    方式一使用 JavaScriptSerializer

    var serializer = new JavaScriptSerializer();
    var obj = serializer.Deserialize<Dictionary<string, string>>(data);

    string accessToken;
    if (!obj.TryGetValue("access_token", out accessToken))
    {
      
    }
    var opentid = obj["openid"];

    方式二 使用 JObject 需要下载 Newtonsoft.Json

    JObject jo = (JObject)JsonConvert.DeserializeObject(result);
    result = jo.GetValue("token").ToString();

     处理null 问题


    JsonConvert.DeserializeObject<orderinfo>(strjson, new JsonSerializerSettings { NullValueHandling = NullValueHandling.Ignore })

       JArray jArray = JArray.Parse(item);
                foreach (JToken jToken in jArray)
                {
                    var job = (JObject)jToken;
                    if (job["item_size"].Value<int>() == 0)

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  • 原文地址:https://www.cnblogs.com/sxmny/p/4572964.html
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