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  • 用SQL删除重复记录的N种方法

    delete from ItemForScore where ifsid not in (
    select min(ifsid) from ItemForScore group by itemid,topflag,isactive having COUNT(-1)>1) 
    and itemid in (select itemid from ItemForScore group by itemid having COUNT(-1)>1)
    例如:  
      id           name         value  
      1               a                 pp  
      2               a                 pp  
      3               b                 iii  
      4               b                 pp  
      5               b                 pp  
      6               c                 pp  
      7               c                 pp  
      8               c                 iii  
      id是主键  
      要求得到这样的结果  
      id           name         value  
      1               a                 pp  
      3               b                 iii  
      4               b                 pp  
      6               c                 pp  
      8               c                 iii 
    
    方法1
    delete   YourTable   
      where   [id]   not   in   (  
      select   max([id])   from   YourTable   
      group   by   (name   +   value))  
     
    方法2
    delete   a  
      from   表   a   left   join(  
      select   id=min(id)   from   表   group   by   name,value  
      )b   on   a.id=b.id  
      where   b.id   is   null  
     
     
     
    查询及删除重复记录的SQL语句
    查询及删除重复记录的SQL语句
    1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
    select * from people
    where peopleId in (select   peopleId from   people group by   peopleId having count(peopleId) > 1)
    2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
    delete from people
    where peopleId in (select   peopleId from people group by   peopleId   having count(peopleId) > 1)
    and rowid not in (select min(rowid) from   people group by peopleId having count(peopleId )>1)
    3、查找表中多余的重复记录(多个字段)
    select * from vitae a
    where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
    delete from vitae a
    where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
    
    5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
    select * from vitae a
    where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
    and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
    (二)
    比方说
    在A表中存在一个字段“name”,
    而且不同记录之间的“name”值有可能会相同,
    现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
    Select Name,Count(*) From A Group By Name Having Count(*) > 1
    如果还查性别也相同大则如下:
    Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1
    
    (三)
    方法一
    declare @max integer,@id integer
    declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1
    open cur_rows
    fetch cur_rows into @id,@max
    while @@fetch_status=0
    begin
    select @max = @max -1
    set rowcount @max
    delete from 表名 where 主字段 = @id
    fetch cur_rows into @id,@max
    end
    close cur_rows
    set rowcount 0 方法二
    "重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。
      1、对于第一种重复,比较容易解决,使用
    select distinct * from tableName
      就可以得到无重复记录的结果集。
      如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除
    select distinct * into #Tmp from tableName
    drop table tableName
    select * into tableName from #Tmp
    drop table #Tmp
      发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。
      2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下
      假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集
    select identity(int,1,1) as autoID, * into #Tmp from tableName
    select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
    select * from #Tmp where autoID in(select autoID from #tmp2)
      最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)
    (四)
    查询重复
    select * from tablename where id in (
    select id from tablename
    group by id
    having count(id) > 1
    )
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  • 原文地址:https://www.cnblogs.com/systemnet123/p/3010115.html
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