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  • 删除表中重复记录,只保留一行

    1. 我用的SQL语句:
    2. delete from fp_sgfpxx    
      where fphm in (select fphm from fp_sgfpxx group by fphm   having count(fphm) > 1)   
      and rowid not in (select min(rowid) from fp_sgfpxx group by fphm having count(fphm )>1)
    3. 删除重复的发票号码
    4. 查询同一表内多字段同时重复记录的SQL语句   
    5. 来自:7th string   
    6.   
    7.   
    8. 比如现在有一人员表   (表名:peosons)   
    9. 若想将姓名、身份证号、住址这三个字段完全相同的记录查询出来 select    p1.*    from    persons    p1,persons    p2    where    p1.id<>p2.id    and    p1.cardid    =    p2.cardid    and    p1.pname    =    p2.pname    and    p1.address    =    p2.address   
    10. 可以实现上述效果.   
    11. 几个删除重复记录的SQL语句   
    12.       
    13. 1.用rowid方法   
    14. 2.用group by方法   
    15. 3.用distinct方法   
    16.       
    17. 1。用rowid方法   
    18. 据据Oracle带的rowid属性,进行判断,是否存在重复,语句如下:   
    19. 查数据:   
    20.       select * from table1 a where rowid !=(select    max(rowid)      
    21.       from table1 b where a.name1=b.name1 and a.name2=b.name2......)   
    22. 删数据:   
    23.      delete    from table1 a where rowid !=(select    max(rowid)      
    24.       from table1 b where a.name1=b.name1 and a.name2=b.name2......)   
    25. 2.group by方法   
    26. 查数据:   
    27.   select count(num), max(name) from student --列出重复的记录数,并列出他的name属性   
    28.   group by num   
    29.   having count(num) >1 --按num分组后找出表中num列重复,即出现次数大于一次   
    30. 删数据:   
    31.   delete from student   
    32.   group by num   
    33.   having count(num) >1   
    34.   这样的话就把所有重复的都删除了。   
    35. 3.用distinct方法 -对于小的表比较有用   
    36. create table table_new as    select distinct *    from table1 minux   
    37. truncate table table1;   
    38. insert into table1 select * from table_new;   
    39.   
    40.   
    41. 查询及删除重复记录的方法大全   
    42.   
    43. 1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断   
    44. select * from people   
    45. where peopleId in (select   peopleId   from   people   group   by   peopleId   having   count(peopleId) > 1)   
    46.   
    47.   
    48. 2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录   
    49. delete from people   
    50. where peopleId   in (select   peopleId   from people   group   by   peopleId    having   count(peopleId) > 1)   
    51. and rowid not in (select min(rowid) from   people   group by peopleId   having count(peopleId )>1)   
    52.   
    53.   
    54. 3、查找表中多余的重复记录(多个字段)   
    55. select * from vitae a   
    56. where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq   having count(*) > 1)   
    57.   
    58.   
    59. 4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录   
    60. delete from vitae a   
    61. where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)   
    62. and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)   
    63.   
    64.   
    65. 5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录   
    66. select * from vitae a   
    67. where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)   
    68. and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)   
    69.   
    70.   
    71. (二)   
    72. 比方说   
    73. 在A表中存在一个字段“name”,   
    74. 而且不同记录之间的“name”值有可能会相同,   
    75. 现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;   
    76. Select Name,Count(*) From A Group By Name Having Count(*) > 1   
    77. 如果还查性别也相同大则如下:   
    78. Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1   
    79.   
    80.   
    81. (三)   
    82. 方法一   
    83. declare @max integer,@id integer   
    84. declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1   
    85. open cur_rows   
    86. fetch cur_rows into @id,@max   
    87. while @@fetch_status=0   
    88. begin   
    89. select @max = @max -1   
    90. set rowcount @max   
    91. delete from 表名 where 主字段 = @id   
    92. fetch cur_rows into @id,@max   
    93. end   
    94. close cur_rows   
    95. set rowcount 0   
    96.   
    97.   
    98. 方法二   
    99. "重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。   
    100.   
    101.   
    102.   1、对于第一种重复,比较容易解决,使用   
    103. select distinct * from tableName   
    104.   就可以得到无重复记录的结果集。   
    105.   如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除   
    106. select distinct * into #Tmp from tableName   
    107. drop table tableName   
    108. select * into tableName from #Tmp   
    109. drop table #Tmp   
    110.   发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。   
    111.   
    112.   
    113.   2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下   
    114.   假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集   
    115. select identity(int,1,1) as autoID, * into #Tmp from tableName   
    116. select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID   
    117. select * from #Tmp where autoID in(select autoID from #tmp2)   
    118.   最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)   
    119.   
    120.   
    121. (四)   
    122. 查询重复   
    123. select * from tablename where id in (   
    124. select id from tablename   
    125. group by id   
    126. having count(id) > 1   
    127. )
    128. ===========================
    129. 在几千条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复的呢?谢谢!
      1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
      select * from people
      where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)

      2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
      delete from people
      where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
      and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

      3、查找表中多余的重复记录(多个字段)
      select * from vitae a
      where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

      4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
      delete from vitae a
      where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
      and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

      5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
      select * from vitae a
      where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
      and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

      比方说在A表中存在一个字段“name”,而且不同记录之间的“name”值有可能会相同,
      现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
      Select Name,Count(*) From A Group By Name Having Count(*) > 1

      如果还查性别也相同大则如下:
      Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

      2.group by方法

      查数据:
        select count(num), max(name) from student --列出重复的记录数,并列出他的name属性
        group by num
        having count(num) >1 --按num分组后找出表中num列重复,即出现次数大于一次
      删数据:
        delete from student
        group by num
        having count(num) >1
        这样的话就把所有重复的都删除了。

      3.用distinct方法 -对于小的表比较有用

      create table table_new as select distinct * from table1 minux
      truncate table table1;
      insert into table1 select * from table_new;


      delete select a.* from FLRK1 a inner join FLRK1 b on a.记录号=b.记录号 and
      (a.[ID]=b.[ID] and a.入库日期=b.入库日期 and a.操作时间=b.操作时间)

      delete from FLRK1 where 记录号 in
      (select min(记录号) from FLRK1 group by 记录号 having count(记录号)>1)


      A表结构:

      ID RQ SJ C
      --------------------------------------------
      1 2005-07-14 14:20:50 A1
      2 2005-02-15 05:12:23 A1
      3 2005-07-14 14:20:50 A1
      4 2005-06-16 16:16:16 A2
      5 2005-06-16 16:16:16 A2
      6 2005-05-18 05:10:35 A3
      7 2005-02-15 05:12:23 A1

      --------------------------------------------

      求SQL语句一条,把表A中 RQ,SJ,C 三个字段有相同的重复记录删除.

      得到的结果:

      ID RQ SJ C
      --------------------------------------------
      1 2005-07-14 14:20:50 A1
      2 2005-02-15 05:12:23 A1
      4 2005-06-16 16:16:16 A2
      6 2005-05-18 05:10:35 A3
      --------------------------------------------

      Delete from A Where ID Not In (Select Min(ID) from A Group By RQ,SJ,C )

      Delete a from tb a inner join tb as b on a.fid <b.fid and a.c=b.c and a.rq=b.rq and a.sj=b.sj

      delete from A t
      where exists(select 1 from A where ID <A.ID and SJ=t.SJ and RQ=t.RQ and C=t.c)


      方法一

      declare @max integer,@id integer
      declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) > 1
      open cur_rows
      fetch cur_rows into @id,@max
      while fetch_status=0
      begin
      select @max = @max -1
      set rowcount @max
      delete from 表名 where 主字段 = @id
      fetch cur_rows into @id,@max
      end
      close cur_rows
      set rowcount 0

        方法二

        有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。

        1、对于第一种重复,比较容易解决,使用

      select distinct * from tableName


        就可以得到无重复记录的结果集。
        如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除

      select distinct * into #Tmp from tableName
      drop table tableName
      select * into tableName from #Tmp
      drop table #Tmp

        发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。

        2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下

        假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集

      select identity(int,1,1) as autoID, * into #Tmp from tableName
      select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
      select * from #Tmp where autoID in(select autoID from #tmp2)

        最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)

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  • 原文地址:https://www.cnblogs.com/tangself/p/1618617.html
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