[GO] GO语言gin框架实现管理员认证登陆接口

后台用户登录验证功能是很多项目的必须要有的逻辑 , 也是常见的技术需求 .

要实现这个逻辑首先要有数据库表结构如下:

CREATE TABLE `user` (
 `id` int(11) NOT NULL AUTO_INCREMENT,
 `name` varchar(50) NOT NULL DEFAULT '',
 `password` varchar(50) NOT NULL DEFAULT '',
 `nickname` varchar(50) NOT NULL DEFAULT '',
 `created_at` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
 `updated_at` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
 `deleted_at` timestamp NULL DEFAULT NULL,
 `avator` varchar(100) NOT NULL DEFAULT '',
 PRIMARY KEY (`id`),
 KEY `idx_name` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8

gin框架路由入口去获取post的数据

func LoginCheckPass(c *gin.Context) {
    password := c.PostForm("password")
    username := c.PostForm("username")

    info, uRole, ok := CheckKefuPass(username, password)
    userinfo := make(map[string]interface{})
    if !ok {
        c.JSON(200, gin.H{
            "code": 400,
            "msg":  "验证失败",
        })
        return
    }
    userinfo["name"] = info.Name
    userinfo["kefu_id"] = info.ID
    userinfo["type"] = "kefu"
    if uRole.RoleId != 0 {
        userinfo["role_id"] = uRole.RoleId
    } else {
        userinfo["role_id"] = 2
    }
    userinfo["create_time"] = time.Now().Unix()

    token, _ := tools.MakeToken(userinfo)
    userinfo["ref_token"] = true
    refToken, _ := tools.MakeToken(userinfo)
    c.JSON(200, gin.H{
        "code": 200,
        "msg":  "验证成功,正在跳转",
        "result": gin.H{
            "token":       token,
            "ref_token":   refToken,
            "create_time": userinfo["create_time"],
        },
    })
}

先忽略掉生成token部分 ,只看查询数据库用户名密码部分

func CheckKefuPass(username string, password string) (models.User, models.User_role, bool) {
    info := models.FindUser(username)
    var uRole models.User_role
    if info.Name == "" || info.Password != tools.Md5(password) {
        return info, uRole, false
    }
    uRole = models.FindRoleByUserId(info.ID)

    return info, uRole, true
}

model里面

func FindUser(username string) User {
    var user User
    DB.Where("name = ?", username).First(&user)
    return user
}