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  • 剑指 Offer 47. 礼物的最大价值

    public int maxValue(int[][] grid) {
            //动态规划
            int m = grid.length;
            int n = grid[0].length;
            for(int i = 1;i<n;i++){
                grid[0][i] = grid[0][i] + grid[0][i-1];
            }
            for(int i = 1;i<m;i++){
                grid[i][0] = grid[i][0] + grid[i-1][0];
            }
            for(int i = 1;i<m;i++){
                for(int j = 1;j<n;j++){
                    grid[i][j] = Math.max(grid[i-1][j],grid[i][j-1]) + grid[i][j];
                }
            }
            return grid[m-1][n-1];
        }


    class Solution {
        public int maxValue(int[][] grid) {
            if(grid.length == 0 || grid[0].length == 0){
                return 0;
            }
            int[][] log = new int[grid.length][grid[0].length];
            return dfs_47(grid,log,0,0);
        }
    
        private int dfs_47(int[][] grid, int[][] log, int row, int col) {
            if(row == grid.length -1  && col == grid[0].length-1){
                return grid[row][col];
            }
    
            if(row>=grid.length || col>=grid[0].length){
                return 0;
            }
            if(log[row][col] > 0){
                return log[row][col];
            }
            int right =  dfs_47(grid,log,row,col + 1);
            int down = dfs_47(grid,log,row+1,col);
            int max = Math.max(right,down) + grid[row][col];
            log[row][col] = max;
            return max;
        }
    }

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  • 原文地址:https://www.cnblogs.com/taoyuxin/p/13556783.html
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