zoukankan      html  css  js  c++  java
  • 将数字转换为汉字书写模式

    面试i遇到这样一个题:

    将23009912340转换为"二百三十亿零九百九十一万二千三百四十",当时没想到什么好的方法,个人感觉"零"最难处理,代码如下:

    import java.util.HashMap;
    import java.util.Map;
    import java.util.Set;
    
    public class ToChina {
    
        public static final String[] st = new String[] { "千", "百", "十", "" };
    
        public String convert(int i) {
            String china = null;
            switch (i) {
            case 0:
                china = "零";
                break;
            case 1:
                china = "一";
                break;
            case 2:
                china = "二";
                break;
            case 3:
                china = "三";
                break;
            case 4:
                china = "四";
                break;
            case 5:
                china = "五";
                break;
            case 6:
                china = "六";
                break;
            case 7:
                china = "七";
                break;
            case 8:
                china = "八";
                break;
            case 9:
                china = "九";
                break;
            }
            return china;
        }
    
        public Map<String, Boolean> buildComplete(String s) {
            char[] chars = s.toCharArray();
            String[] strs = new String[] { null, null, null, null };
            int nullnum = 4 - s.length();
            StringBuffer sb = new StringBuffer();
            for (int i = 0; i < chars.length; i++) {
                strs[i + nullnum] = String.valueOf(chars[i]);
            }
            Boolean flag = false;
            Boolean f = false;
            for (int i = strs.length - 1; i >= 0; i--) {
                if (f == false && strs[i] != null && strs[i].equals("零")) {
                    strs[i] = null;
                    flag = true;
                }
                if (strs[i] != null && !strs[i].equals("零")) {
                    f = true;
                    break;
                }
    
            }
            Boolean b = false;
            for (int i = 0; i < 4; i++) {
                if (strs[i] != null) {
                    if (!strs[i].equals("零")) {
                        sb.append(strs[i] + st[i]);
                    }
                    if (strs[i].equals("零") && b == false) {
                        sb.append(strs[i]);
                        b = true;
                    }
                }
            }
            Map<String, Boolean> map = new HashMap<String, Boolean>();
            map.put(sb.toString(), flag);
            return map;
        }
    
        public String[] split(String str) {
            int length = str.length();
            int num = length / 4;
            int mo = length % 4;
            String[] ss = mo > 0 ? new String[num + 1] : new String[num];
            if (length <= 4) {
                ss = new String[] { str };
            } else {
                for (int i = 0; i < ss.length; i++) {
                    if (i == 0) {
                        ss[i] = str.substring(0, mo);
                    } else {
                        ss[i] = str.substring(mo + (i - 1) * 4, mo + (i) * 4);
                    }
                }
            }
            return ss;
        }
    
        public String danwei(Map<String, Boolean> map, int i, Boolean flag) {
            String v = null;
            if (i == 3) {
                v = "兆";
            }
            if (i == 2) {
                v = "亿";
            }
            if (i == 1) {
                v = "万";
            }
            if (i == 0) {
                v = "";
            }
            StringBuffer sb = new StringBuffer();
            Set<String> keyset = map.keySet();
            for (String key : keyset) {
                if (!key.equals("")) {
                    sb.append(key);
                    sb.append(v);
                    if (map.get(key) == true && i != 0) {
                        sb.append("零");
                    }
                    if (flag == true) {
                        sb.deleteCharAt(0);
                    }
                }
            }
            return sb.toString();
        }
    
        public String result(String str) {
            StringBuffer sb = new StringBuffer();
            String[] strs = this.split(this.convertAll(str));
            int k = 1;
            for (int i = 0; i < strs.length; i++) {
                int j = strs.length - k;
                k += 1;
                boolean flag = false;
                if (i - 1 >= 0) {
                    Map map = this.buildComplete(strs[i - 1]);
                    Set<String> keyset = map.keySet();
                    for (String key : keyset) {
                        flag = (Boolean) map.get(key);
                        break;
                    }
                }
                String s = this.danwei(this.buildComplete(strs[i]), j, flag);
                sb.append(s);
            }
            return sb.toString();
        }
    
        public String convertAll(String str) {
            char[] chars = str.toCharArray();
            String[] cs = new String[chars.length];
            for (int i = 0; i < chars.length; i++) {
                cs[i] = this.convert(Integer.valueOf(String.valueOf(chars[i])));
            }
            StringBuffer sb = new StringBuffer();
            for (int i = 0; i < cs.length; i++) {
                sb.append(cs[i]);
            }
            return sb.toString();
        }
    
        public static void main(String[] args) {
            ToChina t = new ToChina();
            System.out.print(t.result("23009912340"));
        }
    
    }
  • 相关阅读:
    krakend 扩展开发概述
    varnish/api-gateway-benchmarks api gateway 性能压测工具
    krakend 加速配置工具
    krakend 支持发布订阅后端
    krakend 消费amqp mq 消息
    krakend cache 后端请求
    krakend 请求流量镜像的处理
    krakend 请求&&相应的检查
    krakend 的静态proxy
    krakend 的串行proxy
  • 原文地址:https://www.cnblogs.com/tatame/p/2636830.html
Copyright © 2011-2022 走看看