PAT A1132 Cut Integer （20 分）——数学题

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <2​31​​). It is guaranteed that the number of digits of Z is an even number.

Output Specification:

For each case, print a single line Yes if it is such a number, or No if not.

Sample Input:

3
167334
2333
12345678

Sample Output:

Yes
No
No

 

#include <stdio.h>
#include <string>
#include <iostream>
using namespace std;
int s2n(string s){
  int res=0;
  for(int i=0;i<s.length();i++){
    res = 10*res + s[i]-'0';
  }
  return res;
}
int main(){
  string s;
  int n;
  scanf("%d",&n);
  for(int i=0;i<n;i++){
    cin>>s;
    int pos=s.length()/2;
    string s1,s2;
    int n1,n2;
    s1=s.substr(0,pos);
    s2=s.substr(pos,s.length()-pos);
    n1=s2n(s1);
    n2=s2n(s2);
    if((n1==0 || n2==0) || s2n(s)%(n1*n2)!=0)printf("No
");
    else printf("Yes
");
  }
}

注意点：后面两个测试点是其中一半为0的情况，要额外判断。显示浮点错误说明除数遇到了0。