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  • 序列中对应列的值相加 分类: python 小练习 2013-12-05 19:09 293人阅读 评论(0) 收藏

    #coding:utf-8
    
    '''
    
    对应列的值相加
    
    '''
    a=['8533873.000000', '4922178.500000', '7.419005', '63.000282', '59']
    b=['8422450.000000', '4791319.500000', '9.877247', '63.003777', '58']
    c=['8617203.000000', '4774758.000000', '12.711574', '63.007469', '59']
    
    
    def main():
        d=[i for i in zip(a,b,c)]
    
        g=lambda m,n:eval(str(m))+eval(str(n))
    
        print d
    
        print [reduce(g,i)  for i in d]
    
        #方法二
        print [sum([eval(k) for k in i]) for i in d]
    
    
    if __name__ == '__main__':
        main()
    
    '''
    结果:
    
    [('8533873.000000', '8422450.000000', '8617203.000000'), ('4922178.500000', '4791319.500000', '4774758.000000'), ('7.419005', '9.877247', '12.711574'), ('63.000282', '63.003777', '63.007469'), ('59', '58', '59')]
    
    [25573526.0, 14488256.0, 30.007826, 189.011528, 176]
    
    [25573526.0, 14488256.0, 30.007826, 189.011528, 176]
    
    '''


    版权声明:本文为博主原创文章,未经博主允许不得转载。

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  • 原文地址:https://www.cnblogs.com/think1988/p/4627998.html
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