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  • 2017-9-9 NOIP模拟赛

    站军姿

    2bc*cosA=b^2+c^2-a^2

    #include<cstdio>
    #include<cstdlib>
    #include<cmath>
    #include<iostream>
    #include<algorithm>
    const double pi=3.14159265358979323846264;
    using namespace std;
    void work()
    {
        int x1,y1,r1,x2,y2,r2;
        scanf("%lf%lf%lf%lf%lf%lf",&x1,&y1,&r1,&x2,&y2,&r2);
        double d=sqrt(abs(x1-x2)*abs(x1-x2)+abs(y1-y2)*abs(y1-y2));
        if(r1+r2<=d)//相离 
        {
            double ans=r1*r1*pi+r2*r2*pi;
            printf("%.3lf
    ",ans);
            return;
        }
        if(r1+r2>d&&abs(r1-r2)>=d)//内含 
        {
            double ans=max(r2,r1)*max(r2,r1)*pi;
            printf("%.3lf
    ",ans);
            return;
        }
        //相交 
        double ans=r1*r1*pi+r2*r2*pi;
        double j1=acos((d*d+r1*r1-r2*r2)/(2*d*r1));
        double j2=acos((d*d+r2*r2-r1*r1)/(2*d*r2));
        ans-=(r1*r1*j1+r2*r2*j2);
        ans+=d*r1*sin(j1);
        printf("%.3lf
    ",ans);
    }
    int main()
    {
        //freopen("jh.in","r",stdin);
        freopen("standing.in","r",stdin);
        freopen("standing.out","w",stdout);
        int T;scanf("%d",&T);
        while(T--)
        {
            work();
        }
        return 0;
    }
    100分

    对刚

    3

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #define maxn 100010
    using namespace std;
    int n,t,sum;
    bool vis[maxn];
    struct node{
        int nxt,pre;
    }q[maxn];
    int main(){
        //freopen("Cola.txt","r",stdin);
        freopen("resist.in","r",stdin);
        freopen("resist.out","w",stdout);
        scanf("%d%d",&n,&t);
        sum=n-1;
        for(int i=1;i<=n;i++){
            q[i].pre=i-1;q[i].nxt=i+1;
        }
        q[1].pre=n;q[n].nxt=1;
        int pos=1,cnt=0;
        while(sum){
            cnt++;
            if(cnt==t){
                q[q[pos].pre].nxt=q[pos].nxt;
                q[q[pos].nxt].pre=q[pos].pre;
                vis[pos]=1;
                sum--;
                cnt=0;
            }
            pos=q[pos].nxt;
        }
        for(int i=1;i<=n;i++){
            if(!vis[i]){
                printf("%d",i);
                return 0;
            }
        }
    }
    100分 链表模拟

    隔壁

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    using namespace std;
    #define maxn 1010
    int n,m,a[maxn],b[maxn],c[maxn];
    long long map[maxn][maxn];
    long long ans1,ans2;
    bool v1[maxn];
    int main(){
        //freopen("Cola.txt","r",stdin);
        freopen("neighbor.in","r",stdin);
        freopen("neighbor.out","w",stdout);
        scanf("%d%d",&n,&m);
        for(int i=1;i<=n;i++)scanf("%d",&c[i]);
        for(int i=1;i<=m;i++)scanf("%d",&b[i]);
        for(int i=1,j=n;i<=n;i++,j--)a[i]=c[j];
        int mark;
        for(int i=1;i<=n;i++){
            bool flag=0;
            for(int j=1;j<=m;j++){
                if(b[j]==a[i]&&!v1[j]){
                    v1[j]=1;
                    ans1+=a[i];
                    flag=1;
                    break;
                }
                if(b[j]>a[i])mark=j;
            }
            if(!flag){
                ans1+=a[i];
            }
        }
        for(int i=1;i<=m;i++){
            if(!v1[i]){
                ans1+=b[i];
            }
        }
        cout<<ans1<<' ';
        for(int i=1;i<=n;i++){
            for(int j=1;j<=m;j++){
                if(b[j]>=a[i])
                    map[i][j]=a[i];
            }
        }
        for(int i=1;i<=n;i++){
            for(int j=1;j<=m;j++){
                if(b[j]<=a[i])
                    map[i][j]=b[j];
                ans2+=map[i][j];
            }
        }
        cout<<ans2;
        return 0;
    }
    100分 贪心
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  • 原文地址:https://www.cnblogs.com/thmyl/p/7497496.html
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