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  • 2017-10-20 NOIP模拟赛

    Lucky Transformation

    #include<iostream>
    #include<cstring>
    #include<cstdio>
    using namespace std;
    int n,k,cnt;
    char s[1000010];
    int main(){
        freopen("trans.in","r",stdin);freopen("trans.out","w",stdout);
        //freopen("Cola.txt","r",stdin);
        while(scanf("%d%d",&n,&k)!=EOF){
            scanf("%s",s);cnt=0;
            int rest=0;
            for(int i=0;i<n;i++){
                if(s[i]=='2'&&s[i+1]=='3'){
                    if(i>0&&(i+1)%2==0&&s[i-1]=='2'&&s[i+1]=='3'){
                        rest=k-cnt;break;
                    }
                    else if((i+1)%2==1&&s[i+1]=='3'&&s[i+2]=='3'){
                        rest=k-cnt;break;
                    }
                    else{
                        if((i+1)%2==0)s[i]='3';
                        else s[i+1]='2';
                        cnt++;
                        if(cnt==k)break;
                    }
                }
            }
            rest%=2;
            if(rest==0||cnt==k){
                printf("%s
    ",s);
            }
            else{
                for(int i=0;i<n;i++){
                    if(s[i]=='2'&&s[i+1]=='3'){
                        if((i+1)%2==0)s[i]='3';
                        else s[i+1]='2';
                        break;
                    }
                }
                printf("%s
    ",s);
            }
        }
    }
    100分 规律

    Snake vs Block

    #include<iostream>
    #include<cstdio>
    #define maxn 210
    using namespace std;
    int n,m,map[maxn][7],num,ans,head[maxn],edge[maxn*6+10][maxn*6+10];
    struct node{
        int to,pre,v;
    }e[maxn*7*3];
    int make_id(int i,int j){return (i-1)*5+j;}
    void Insert(int from,int to,int v){
        e[++num].to=to;
        e[num].v=v;
        e[num].pre=head[from];
        head[from]=num;
        edge[from][to]=num;
    }
    void dfs(int x,int y,int sc,int len){
        if(x>n){
            ans=max(ans,sc);
            return;
        }
        int now=make_id(x,y);
        for(int i=head[now];i;i=e[i].pre){
            int to=e[i].to;
            if(e[i].v==0)continue;
            int xx=(to-1)/5+1,yy=to%5;
            if(yy==0)yy=5;
            e[i].v=0;
            if(map[xx][yy]>=0){
                int p=map[xx][yy];
                map[xx][yy]=0;
                dfs(xx,yy,sc,len+p);
                map[xx][yy]=p;
            }
            else {
                if(len+map[xx][yy]<0){ans=max(ans,sc);}
                else {
                    int p=map[xx][yy];
                    map[xx][yy]=0;
                    dfs(xx,yy,sc-p,len+p);
                    map[xx][yy]=p;
                }
            }
            e[i].v=1;
        }
    }
    int main(){
        freopen("snakevsblock.in","r",stdin);freopen("snakevsblock.out","w",stdout);
        //freopen("Cola.txt","r",stdin);
        scanf("%d",&n);
        for(int i=1;i<=n;i++)
            for(int j=1;j<=5;j++){
                int id=make_id(i,j);
                if(j!=1)Insert(id,make_id(i,j-1),1);//向左
                if(j!=5)Insert(id,make_id(i,j+1),1);//向右 
                Insert(id,make_id(i+1,j),1);//向下 
                scanf("%d",&map[i][j]);
            }
        scanf("%d",&m);
        int x,y;
        for(int i=1;i<=m;i++){
            scanf("%d%d",&x,&y);
            int id1=make_id(x,y),id2=make_id(x,y+1);
            e[edge[id1][id2]].v=0;
            e[edge[id2][id1]].v=0;
        }
        dfs(1,3,0,4);
        printf("%d",ans);
    }
    30分 建图+dfs
    /*
    把豆豆和砖块丢在一起dp 
    f[i][j][k]:到第i行,蛇的长度还剩下j,从k位置出第i行的最大得分 
    g[j][l][r]:蛇的长度剩下j,从当前行l到r区间内仍为死亡的最大得分 
    初始化:对于每个i,g[j][k][k]=f[i-1][j-a[i][k]][k]+max(-a[i][k],0) 为初始状态 
    方程g[j][l][r] = max(g[j-a[i][l]][l+1][r] + max(-a[i][j],0),g[j-a[i][r]][l][r-1]+max(-a[i][k],0)); 
    最后f[i][j][k] = max{g[j][l][r](1≤l≤k ≤r ≤5)} 
    */
    #include<iostream>
    #include<cstdio>
    #include<cstring>
    
    #define N 207
    #define M 10005
    
    using namespace std;
    int a[N][5],f[N][M][5],g[M][5][5];
    bool flag[N][4];
    int n,m,maxi,ans,val;
    
    inline int read()
    {
        int x=0,f=1;char c=getchar();
        while(c>'9'||c<'0'){if(c=='-')f=-1;c=getchar();}
        while(c>='0'&&c<='9'){x=x*10+c-'0';c=getchar();}
        return x*f;
    }
    
    int main()
    {
        freopen("snakevsblock.in","r",stdin);
        freopen("snakevsblock.out","w",stdout);
        n=read();int x,y;
        for(int i=1;i<=n;i++) for(int j=0;j<5;j++)
          a[i][j]=read();
        m=read();
        for(int i=1;i<=m;i++)
        {
            x=read();y=read();
            flag[x][y-1]=1;
        }
        memset(f,-0x7f7f7f,sizeof f);
        f[0][4][2]=0;maxi=n*50;
        
        for(int i=1;i<=n;i++)
        {
            memset(g,-0x7f7f7f,sizeof g);
            for(int j=0;j<=maxi;j++)
              for(int k=0;k<5;k++)
                if(j-a[i][k]>=0 && j-a[i][k]<=maxi)
                  f[i][j][k]=g[j][k][k]=f[i-1][j-a[i][k]][k]+max(-a[i][k],0);
    
            for(int l=1;l<=4;l++)
              for(int j=0,k=j+l;k<5;j++,k++)
                for(int v=0;v<=maxi;v++)
                {
                    if(!flag[i][j]  && (val=v-a[i][j])>=0 && val<=maxi) g[v][j][k] = g[val][j + 1][k] + max(-a[i][j], 0);//g[v][j][k]=max(g[v][j][k],g[val][j+1][k]+max(-a[i][j],0));
                    if(!flag[i][k-1]&& (val=v-a[i][k])>=0 && val<=maxi) g[v][j][k]=max(g[v][j][k],g[val][j][k-1]+max(-a[i][k],0));
                    for(int to=j;to<=k;to++) f[i][v][to]=max(f[i][v][to],g[v][j][k]);
                }
        }
        
        for(int i=0;i<=n;i++)
          for(int j=0;j<=maxi;j++)
            for(int k=0;k<5;k++)
              ans=max(f[i][j][k],ans);
              
        printf("%d
    ",ans);
        return 0;
    }
    100分 动态规划

    Ping

    #include<iostream>
    #include<cstring>
    #include<cstdio>
    #define maxn 100010
    using namespace std;
    int n,m,k,num,head[maxn],fa[maxn],dep[maxn],h[maxn],cnt;
    bool vis[maxn],v[maxn];
    int c[16][1<<15];
    struct node{
        int to,pre;
    }e[maxn*2];
    struct Node{
        int l,r;
    }p[300010];
    void Insert(int from,int to){
        e[++num].to=to;
        e[num].pre=head[from];
        head[from]=num;
    }
    int count(int x){
        int res=0;
        while(x){
            if(x&1)res++;
            x>>=1;
        }
        return res;
    }
    void dfs(int now,int father){
        fa[now]=father;dep[now]=dep[father]+1;
        for(int i=head[now];i;i=e[i].pre){
            int to=e[i].to;
            if(to==father)continue;
            dfs(to,now);
        }
    }
    int sta;
    bool lca(int a,int b){
        if(vis[a]||vis[b])return 1;
        if(dep[a]<dep[b])swap(a,b);
        while(dep[a]>dep[b]){
            a=fa[a];
            if(vis[a])return 1;
        }
        while(a!=b){
            a=fa[a];b=fa[b];
            if(vis[a]||vis[b])return 1;
        }
        return 0;
    }
    bool ok(int s){
        memset(vis,0,sizeof(vis));
        int pos=0;
        while(s){
            pos++;
            if(s&1)vis[h[pos]]=1;
            s>>=1;
        }
        for(int i=1;i<=k;i++){
            int a=p[i].l,b=p[i].r;
            if(lca(a,b))continue;
            else return 0;
        }
        return 1;
    }
    bool check(int x){
        for(int i=1;i<=c[x][0];i++){
            int s=c[x][i];
            if(ok(s)){
                sta=s;
                return 1;
            }
        }
        return 0;
    }
    int main(){
        freopen("ping.in","r",stdin);freopen("ping.out","w",stdout);
        //freopen("Cola.txt","r",stdin);
        scanf("%d%d",&n,&m);
        for(int i=0;i<=(1<<n)-1;i++){
            int nu=count(i);
            c[nu][++c[nu][0]]=i;
        }
        int x,y;
        for(int i=1;i<=m;i++){
            scanf("%d%d",&x,&y);
            Insert(x,y);Insert(y,x);
            if(!v[x])h[++cnt]=x,v[x]=1;
            if(!v[y])h[++cnt]=y,v[y]=1;
        }
        dfs(1,1);
        scanf("%d",&k);
        for(int i=1;i<=k;i++)
            scanf("%d%d",&p[i].l,&p[i].r);
        int l=1,r=cnt,ans=0;
        while(l<=r){
            int mid=(l+r)>>1;
            if(check(mid))ans=mid,r=mid-1;
            else l=mid+1;
        }
        printf("%d
    ",ans);
        int pos=0;
        while(sta){
            pos++;
            if(sta&1)printf("%d ",h[pos]);
            sta>>=1;
        }
        return 0;
    }
    30分 二分答案
    #include <bits/stdc++.h>
    using namespace std;
    int n, m, P, u, v, to[200005], nxt[200005], p[100005], deep[100005], q[500005][2];
    int son[100005], fa[100005], size[100005], top[100005], dfsx[100005], cnt, ans;
    int lca[500005], Q[500005], lr[100005][2];
    int sta[100005];
    bool flag[400005];
    void dfs(int x)
    {
        size[x] = 1;
        for (int i = p[x]; i != -1; i = nxt[i])
            if (to[i] != fa[x])
            {
                fa[to[i]] = x;
                deep[to[i]] = deep[x] + 1;
                dfs(to[i]);
                if (son[x] == -1 || size[to[i]] > size[son[x]]) son[x] = to[i];
                size[x] += size[to[i]];
            }
    }
    void dfs1(int x)
    {
        dfsx[x] = ++cnt;
        if (son[x] != -1) top[son[x]] = top[x], dfs1(son[x]);
        for (int i = p[x]; i != -1; i = nxt[i])
            if (to[i] != fa[x] && to[i] != son[x])
                top[to[i]] = to[i], dfs1(to[i]);
    }
    int findlca(int x, int y)
    {
        while (1)
        {
            if (top[x] == top[y]) return deep[x] > deep[y]? y : x;
            if (deep[top[x]] > deep[top[y]]) x = fa[top[x]];
            else y = fa[top[y]];
        }
    }
    bool query(int x, int l, int r, int ll, int rr)
    {
        if (l == ll && r == rr) return flag[x];
        int mid = (l + r) >> 1, L = x << 1, R = L | 1;
        if (rr <= mid) return query(L, l, mid, ll, rr);
        else if (ll > mid) return query(R, mid + 1, r, ll, rr);
        else return query(L, l, mid, ll, mid) | query(R, mid + 1, r, mid + 1, rr);
    }
    void modify(int x, int l, int r, int to)
    {
        flag[x] = true;
        if (l == r) return;
        int mid = (l + r) >> 1, L = x << 1, R = L | 1;
        if (to <= mid) modify(L, l, mid, to);
        else modify(R, mid + 1, r, to);
    }
    bool Query(int x, int y)
    {
        while (1)
        {
            if (top[x] == top[y])
            {
                if (deep[x] < deep[y]) return query(1, 1, cnt, dfsx[x], dfsx[y]);
                else return query(1, 1, cnt, dfsx[y], dfsx[x]);
            }
            if (deep[top[x]] > deep[top[y]])
                if (query(1, 1, cnt, dfsx[top[x]], dfsx[x])) return true;
                else x = fa[top[x]];
            else
            {
                if (query(1, 1, cnt, dfsx[top[y]], dfsx[y])) return true;
                else y = fa[top[y]];
            }
        }
    }
    void work(int x)
    {
        for (int i = p[x]; i != -1; i = nxt[i])
            if (to[i] != fa[x])
                work(to[i]);
        for (int i = lr[x][0]; i <= lr[x][1]; i++)
            if (!Query(q[Q[i]][0], q[Q[i]][1]))
            {
                modify(1, 1, cnt, dfsx[x]);
                sta[++ans] = x;
                return;
            }
    }
    bool cmp(int x, int y) {return lca[x] < lca[y];}
    int main()
    {
        freopen("ping.in","r",stdin);
        freopen("ping.out","w",stdout);
        scanf("%d%d", &n, &m);
        for (int i = 0; i <= n; i++) p[i] = son[i] = -1, top[i] = size[i] = fa[i] = deep[i] = 0;
        for (int i = 1; i <= n * 4; i++) flag[i] = false;
        for (int i = 1; i <= m; i++)
        {
            scanf("%d%d", &u, &v);
            u--, v--;
            to[i * 2 - 1] = v;
            nxt[i * 2 - 1] = p[u];
            p[u] = i * 2 - 1;
            to[i * 2] = u;
            nxt[i * 2] = p[v];
            p[v] = i * 2;
        }
        deep[0] = 1;
        dfs(0);
        cnt = 0;
        dfs1(0);
        scanf("%d", &P);
        for (int i = 1; i <= P; i++)
        {
            scanf("%d%d", &u, &v);
            u--, v--;
            q[i][0] = u, q[i][1] = v;
            lca[i] = findlca(u, v);
            Q[i] = i;
        }
        sort(Q + 1, Q + P + 1, cmp);
        for (int i = 0; i <= n; i++) lr[i][0] = P + 1, lr[i][1] = 0;
        for (int i = 1; i <= P; i++)
        {
            lr[lca[Q[i]]][0] = min(lr[lca[Q[i]]][0], i);
            lr[lca[Q[i]]][1] = max(lr[lca[Q[i]]][1], i);
        }
        ans = 0;
        work(0);
        printf("%d
    ", ans);
        for (int i = 1; i <= ans; i++) printf("%d ", sta[i] + 1);
        return 0;
    }
    100分
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  • 原文地址:https://www.cnblogs.com/thmyl/p/7698612.html
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