这里我用的空间是x向右为正,y向下为正,z向屏幕里面为正。相当于标准右手系绕x轴旋转了180度。
将三个点光源放在
r = [0.3,0,0.5];
g = [0.3,-0.5*cos(pi/6),-0.5*sin(pi/6)];
b = [0.3,0.5*cos(pi/6),-0.5*sin(pi/6)];
这三个位置上,向四周发射光线,取光线到y-z平面的模的倒数作为光的强度。
图像如下:
程序如下:
clear all; close all; clc; r = [0.3,0,0.5]; g = [0.3,-0.5*cos(pi/6),-0.5*sin(pi/6)]; b = [0.3,0.5*cos(pi/6),-0.5*sin(pi/6)]; imgr1=[];imgr2=[]; imgg1=[];imgg2=[]; imgb1=[];imgb2=[]; for y=-1:0.004:1 imgr1=[];imgg1=[];imgb1=[]; for z=-1:0.004:1 pm=[0,y,z]; lightr=pm-r; lightg=pm-g; lightb=pm-b; imgr=1/norm(lightr); imgg=1/norm(lightg); imgb=1/norm(lightb); imgr1=[imgr1 imgr]; imgg1=[imgg1 imgg]; imgb1=[imgb1 imgb]; end imgr2=[imgr2;imgr1]; imgg2=[imgg2;imgg1]; imgb2=[imgb2;imgb1]; end [h w]=size(imgr2); img=zeros(h,w,3); img(:,:,1) = mat2gray(imgr2); img(:,:,2) = mat2gray(imgg2); img(:,:,3) = mat2gray(imgb2); imshow(img) imwrite(img,'img.png')