1,2,3,5,7,8,10,11,12,13,14,15,16,21,22 》1~3,5,7~8,10~16,21~22

为了省略空间以及符合操作手手工填写纸张的视觉，决定把料架随行卡上的卷号进行归类整理，如

A-3,A-4,A-5,A-8形成A-3~5,8等。

话不多说了，用了几个辅助的List<int>完成，代码如下：

 /// <summary>
/// 类似的1,2,3,5,7,8,10,11,12,13,14,15,16,21,22转换成1~3,5,7~8,10~16,21~22
/// </summary>
/// <param name="strInput">传入字符串，如1,2,3,5,7,8,10,11,12,13,14,15,16,21,22</param>
/// <returns>生成的新字符串，如1~3,5,7~8,10~16,21~22</returns>
private string makeSimpleString(string strInput)
{
    string strOutput = "";
    //把为整数的放到il中
    string[] ss = strInput.Split(',');
    List<int> il = new List<int>();
    for (int i = 0; i < ss.Length; ++i)
    {
        try
        {
            int k = Convert.ToInt32(ss[i]);
            il.Add(k);
        }
        catch
        {
            if (strOutput == "")
                strOutput = ss[i];
            else
                strOutput += "," + ss[i];
        }
    }

    
    if (il.Count > 0)
    {
        //把il中的连续的数各放到不同的List<int>中
        il.Sort();
        List<List<int>> ill = new List<List<int>>();
        int prev = il[0];
        List<int> lTemp = new List<int>();
        lTemp.Add(prev);
        ill.Add(lTemp);
        for (int i = 1; i < il.Count; ++i)
        {
            if (il[i] - prev == 1)
            {
                ill[ill.Count - 1].Add(il[i]);
            }
            else
            {
                lTemp = new List<int>();
                lTemp.Add(il[i]);
                ill.Add(lTemp);
            }
            prev = il[i];
        }

        //生成结果字符串
        for (int i = 0; i < ill.Count; ++i)
        {
            if (ill[i].Count == 1)
            {
                if (strOutput == "")
                    strOutput = ill[i][0].ToString();
                else
                    strOutput += "," + ill[i][0].ToString();
            }
            else
            {
                if (strOutput == "")
                    strOutput = ill[i][0].ToString() + "~" + ill[i][ill[i].Count - 1].ToString();
                else
                    strOutput += "," + ill[i][0].ToString() + "~" + ill[i][ill[i].Count - 1].ToString();
            }
        }
    }

    return strOutput;
}