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  • 2013-2014 ACM-ICPC Pacific Northwest Regional Contest D.Delta Quadrant

    题意略。

    思路:

    由于这是一颗无根树,我们可以贪心地来删去边。

    详见代码:

    #include<bits/stdc++.h>
    using namespace std;
    typedef long long LL;
    const int maxn = 1e4 + 5;
    
    struct edge{
        int from,to,len,id;
        edge(int a = 0,int b = 0,int c = 0,int d = 0){
            from = a,to = b,len = c,id = d;
        }
        bool operator< (const edge& e) const{
            return len < e.len;
        }
    };
    
    int indegree[maxn];
    bool visit[maxn];
    edge store[maxn];
    priority_queue<edge> pq;
    
    void init(){
        memset(visit,false,sizeof(visit));
        memset(indegree,0,sizeof(indegree));
        while(pq.size()) pq.pop();
    }
    
    int main(){
        int T;
        scanf("%d",&T);
        while(T--){
            int n,k;
            LL sum = 0;
            init();
            scanf("%d%d",&n,&k);
            int from,to,len;
            for(int i = 0;i < n - 1;++i){
                scanf("%d%d%d",&from,&to,&len);
                store[i] = edge(from,to,len,i);
                sum += len;
                indegree[from] += 1;
                indegree[to] += 1;
            }
            for(int i = 0;i < n - 1;++i){
                edge& e = store[i];
                if(indegree[e.from] == 1 || indegree[e.to] == 1){
                    pq.push(e);
                    visit[e.id] = true;
                }
            }
            LL ans = 0;
            for(int i = 0;i < k;++i){
                edge e = pq.top();
                pq.pop();
                --indegree[e.from];
                --indegree[e.to];
                ans += e.len;
                for(int j = 0;j < n - 1;++j){
                    if(visit[j]) continue;
                    edge ee = store[j];
                    if(indegree[ee.from] == 1 || indegree[ee.to] == 1){
                        pq.push(ee);
                        visit[ee.id] = true;
                    }
                }
            }
            ans = sum - ans;
            ans *= 2;
            printf("%lld
    ",ans);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/tiberius/p/9382140.html
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