UVALive3093 POJ2105 ZOJ2482 IP Address

IP Address

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 20070		Accepted: 11589

Description

Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are: 

27   26  25  24  23   22  21  20 

128 64  32  16  8   4   2   1 

Input

The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.

Output

The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.

Sample Input

4
00000000000000000000000000000000 
00000011100000001111111111111111 
11001011100001001110010110000000 
01010000000100000000000000000001 

Sample Output

0.0.0.0
3.128.255.255
203.132.229.128
80.16.0.1

Source

México and Central America 2004

Regionals 2004 >> Latin America - Mexico and Central America

问题链接：UVALive3093 POJ2105 ZOJ2482 IP Address

问题描述：参见上文。

问题分析：一个简单的数字串切割和进制转换问题。

程序说明：（略）

参考链接：（略）

AC的C++语言程序：

/* UVALive3093 POJ2105 IP Address */

#include <iostream>
#include <cstdio>

using namespace std;

int main()
{
    int n;
    char c;

    scanf("%d", &n);
    c = getchar();
    while(n--) {
        for(int i=1; i<=4; i++) {
            if(i != 1)
                putchar('.');

            int v = 0;
            for(int j=1; j<=8; j++) {
                c = getchar();
                v = v * 2 + c - '0';
            }
            printf("%d", v);
        }
        printf("
");
        while((c = getchar()) != '
' && c != EOF);
    }

    return 0;
}