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  • The 2018 ACM-ICPC Chinese Collegiate Programming Contest Fight Against Monsters

     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 #include <string>
     5 #include <algorithm>
     6 #include <utility>
     7 #include <vector>
     8 #include <map>
     9 #include <queue>
    10 #include <stack>
    11 #include <cstdlib>
    12 typedef long long ll;
    13 #define lowbit(x) (x&(-x))
    14 #define ls l,m,rt<<1
    15 #define rs m+1,r,rt<<1|1
    16 using namespace std;
    17 int t,n;
    18 const int  N=1e5+9;
    19 struct Node{
    20     int h;
    21     ll w;
    22     int f;
    23 }node[N];
    24 bool cmp(Node x,Node y){
    25     double xx=1.0*x.f/x.w;
    26     double yy=1.0*y.f/y.w;
    27     return xx<yy;
    28 }
    29 /*
    30 最好是先攻击 :被攻击次数越少,并且伤害力又大
    31 也即是按照 
    32 需要被攻击的次数/伤害力
    33 由小到大排序
    34 */
    35 int  main()
    36 {
    37     scanf("%d",&t);
    38     for(int i=1;i<=t;i++)
    39     {  memset(node,0,sizeof(node));
    40         scanf("%d",&n);
    41          ll sum=0;
    42         for(int i=0;i<n;i++){
    43             scanf("%d%lld",&node[i].h,&node[i].w);    
    44             sum+=node[i].w;
    45         }
    46         int k,ans;
    47         for(int i=0;i<n;i++)
    48         {   k=1;
    49             ans=0;
    50             while(node[i].h>0){
    51                 node[i].h-=k;
    52                 k++;
    53                 ans++;
    54             }
    55             node[i].f=ans;
    56         }
    57         sort(node,node+n,cmp);
    58         ll ret=0;    
    59         for(int i=1;i<n;i++)
    60             
    61             {
    62                 node[i].f=node[i-1].f+node[i].f;
    63             }
    64         for(int i=0;i<n;i++)
    65         {
    66             ret+=node[i].f*node[i].w;
    67         }
    68         printf("Case #%d: %lld
    ",i,ret);
    69     }
    70     return 0;
    71 }
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  • 原文地址:https://www.cnblogs.com/tingtin/p/9327538.html
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