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  • set

     1        set<int>s1;
     2     multiset<int>s2;
     3     int  x;
     4     for(int i=1;i<=3;i++)
     5     {
     6         scanf("%d",&x);
     7         s1.insert(x);
     8         s2.insert(x);
     9     }
    10     for(auto it=s1.begin();it!=s1.end();it++){
    11         cout<<*it<<endl;
    12     }
    13     cout<<"frvbfeb
    ";
    14     for(auto it=s2.begin();it!=s2.end();it++){
    15         cout<<*it<<endl;
    16     }
    17     
    18     /*
    19     
    20     
    21     5 1 1
    22 1
    23 5
    24 frvbfeb
    25 1
    26 1
    27 5
    28 
    29 */
    insert
    erase
    clear
    count
     1 //遍历
     2 set<int>s;
     3 int  main()
     4 {
     5    for(int  i=1;i<=3;i++) s.insert(i);
     6    for(auto x :s) printf("%d
    ",x);
     7 }
     8 1
     9 2
    10 3
     1 char c;
     2 int n,y;
     3 set<int>se;
     4 set<int>::iterator it1,it2,it3;
     5 int  main()
     6 {  
     7   for(int i=1;i<=5;i++){
     8       se.insert(i);
     9   }
    10  
    11   it1 = se.begin();
    12   it2 = se.begin();
    13   it2++;it2++;
    14   se.erase(it1,it2);[)
    15   printf("%d
    ",*it2);
    16 
    17   for(it3=se.begin();it3!=se.end();it3++) printf("%d
    ",*it3);
    18     return 0;
    19 }
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  • 原文地址:https://www.cnblogs.com/tingtin/p/9973128.html
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