zoukankan      html  css  js  c++  java
  • poj 1961 Period【求前缀的长度,以及其中最小循环节的循环次数】

    Period
    Time Limit: 3000MS   Memory Limit: 30000K
    Total Submissions: 14653   Accepted: 6965

    Description

    For each prefix of a given string S with N characters (each character has an ASCII code between 97 and 126, inclusive), we want to know whether the prefix is a periodic string. That is, for each i (2 <= i <= N) we want to know the largest K > 1 (if there is one) such that the prefix of S with length i can be written as AK ,that is A concatenated K times, for some string A. Of course, we also want to know the period K.

    Input

    The input consists of several test cases. Each test case consists of two lines. The first one contains N (2 <= N <= 1 000 000) – the size of the string S.The second line contains the string S. The input file ends with a line, having the 
    number zero on it.

    Output

    For each test case, output "Test case #" and the consecutive test case number on a single line; then, for each prefix with length i that has a period K > 1, output the prefix size i and the period K separated by a single space; the prefix sizes must be in increasing order. Print a blank line after each test case.

    Sample Input

    3
    aaa
    12
    aabaabaabaab
    0

    Sample Output

    Test case #1
    2 2
    3 3
    
    Test case #2
    2 2
    6 2
    9 3
    12 4
    题意:求前缀的长度,以及其中最小循环节的循环次数 但是循环次数必须大于1
    #include<stdio.h>
    #include<string.h>
    #define MAX 1000100
    int next[MAX];
    char str[MAX];
    int a[MAX],b[MAX];
    int n,m,k;
    void getfail()
    {
    	int i,j;
    	next[0]=next[1]=0;
    	for(i=1;i<n;i++)
    	{
    		j=next[i];
    		while(j&&str[i]!=str[j])
    		    j=next[j];
    		next[i+1]=str[i]==str[j]?j+1:0;
    	}
    }
    void kmp()
    {
    	int i,j;
    	for(i=1;i<=n;i++)
    	{
    		k=i;
    		if(k==(k-next[k]))//k-next[k]最小循环节长度 
    		continue;
    		if(k%(k-next[k])==0)
    		printf("%d %d
    ",i,k/(k-next[k]));
    	}
    	printf("
    ");
    }
    int main()
    {
    	int i,t=1;
    	while(scanf("%d",&n),n)
    	{
    		getchar();
    		for(i=0;i<n;i++)
    		scanf("%c",&str[i]);
    		getfail();
    		printf("Test case #%d
    ",t++);
    		kmp();
    	}
    	return 0;
    }
    

      

  • 相关阅读:
    oracle中add_months()函数总结
    Oracle总结之plsql编程(基础九)
    Oracle总结之plsql编程(基础八)
    java调用存储过程
    Oracle总结之plsql编程(基础七)
    Python 變量 Variable 動態綁定
    Python 類和對象 Class vs Object
    Python 元組 Tuple
    Python 字典 Dictionary
    Python 列表 List
  • 原文地址:https://www.cnblogs.com/tonghao/p/4712207.html
Copyright © 2011-2022 走看看