zoukankan      html  css  js  c++  java
  • SPOJ #440. The Turtle´s Shortest Path

    Coding a Dijkstra is not hard. %70 of my time spent on tackling TLE, as my last post.

    Dijkstra works in BFS manner, but at each step, it picks the shortest child greedily and then relax all other neighbors. 

    Data Structure: since there could be up to 10000 cities, storing distance for all pairs of cities are not allowed - 300+M space exceeds SPOJ's 256M limit. So I simply used std::map (my another version used GNU's hash_map but not tried its performance) as the adjacent linked list to store graph; and map<string, int> to store city name - index mapping. Again, hash_map could be better.

    Anyway, here's my AC code, 11.34s:

    //    440
    
    #include <vector>
    #include <cstdio>
    #include <iostream>
    #include <queue>
    #include <map>
    using namespace std;
    
    /*
    //////////////////////////////////
    //    Components for GNU's hash_map
    #include <backward/hash_map>
    using namespace __gnu_cxx;
    namespace __gnu_cxx
    {
      template<>
      struct hash<std::string>
      {
        hash<char*> h;
        size_t operator()(const std::string &s) const
        {
          return h(s.c_str());
        };
      };
    }
    */
    //////////////////////////////////
    
    const int MaxCity = 10000;
    const int MaxDist = 0xFFFFFFF;
    map<string, int> hmap;
    typedef map<int, map<int, int> > DHash;
    DHash distMap;
    
    bool visited[MaxCity] = {false};
    int dist[MaxCity] = {MaxDist};
    
    /////////////////////////////////////
    void add_dist(int srcInx, int toInx, int cost)
    {
        distMap[srcInx][toInx] = cost;
    }
    int get_dist(int srcInx, int toInx)
    {
        DHash::iterator iter = distMap.find(srcInx);
        if(iter != distMap.end())
        {
            map<int, int>::iterator iter2 = iter->second.find(toInx);
            if(iter2 != iter->second.end())
            {
                return iter2->second;
            }
        }
        return MaxDist;
    }
    /////////////////////////////////////
    struct nComp
    {
     int operator() (const pair<int,int>& p1, const pair<int,int> &p2)
     {
         return p1.second > p2.second;
     }
    };
    ///////////////////////////////////////
    void clearGraph()
    {
        hmap.clear();
        distMap.clear();
    }
    
    void clearRuntime(int citycnt)
    {
        for(int i = 0; i < citycnt; i ++)
        {
            visited[i] = false;
            dist[i] = MaxDist;
        }
    }
    ///////////////////////////////////////////
    int find_shortest_path(int cinx1, int cinx2)
    {
        int vcnt = hmap.size();
    
        priority_queue<pair<int, int>, vector<pair<int, int> >, nComp> q;
        //    Init
        for(int i = 0; i < vcnt; i ++)
        {
            dist[i] = MaxDist;
            visited[i] = false;
        }
        dist[cinx1 - 1] = 0;
        q.push(make_pair(cinx1-1, 0));
    
        //    Go
        while(!q.empty())
        {
            pair<int,int> n = q.top(); q.pop();
    
            //    Greedy, find the unvisited min-cost node
            int minInx = n.first;
            int minCost = n.second;
            if(minCost == MaxDist)    break;
            visited[minInx] = true;
            if(minInx == cinx2 - 1) return dist[cinx2 - 1];
    
            //    Relax neighbors
            DHash::iterator iter = distMap.find(minInx);
            map<int,int> &child = iter->second;
            for(map<int,int>::iterator iMap = child.begin(); iMap != child.end(); iMap ++)
            {
                int i = iMap->first;
                int gDist = iMap->second;
                int alt = dist[minInx] + gDist;
                if(alt < dist[i])
                {
                    dist[i] = alt;
                    //cout << "		relaxed to " << alt << " " << minInx << " to" << i <<endl;
                    q.push(make_pair(i, dist[i]));
                }
            }
        }
    
        return MaxDist;
    }
    /////////////////////////
    #define gc getchar
    int read_int()
    {
      char c = gc();
      while(c<'0' || c>'9') c = gc();
      int ret = 0;
      while(c>='0' && c<='9') {
        ret = 10 * ret + c - 48;
        c = gc();
      }
      return ret;
    }
    /////////////////////////
    int main()
    {
        int runcnt = read_int();
        //cout << "Run " << runcnt << endl;
        while(runcnt --)
        {
            clearGraph();
            int ccnt = read_int();
            for(int ic = 1; ic <= ccnt; ic ++)
            {
                // cityName -> cityInx
                string city_name; cin >> city_name;
                int nnbr = read_int();
                hmap.insert(map<string, int>::value_type(city_name, ic));
                //cout << city_name << "->" << ic << endl;
    
                //    Fill out adjacency matrix
                while(nnbr--)
                {
                    int cinx = read_int();
                    int cost = read_int();
                    add_dist(ic-1, cinx-1, cost);
                    //cout << ic << " <-> " << cinx << " = " << cost << endl;
                }
            }
    
            int qcnt  = read_int();
            while(qcnt --)
            {
                string c1, c2;
                cin >> c1 >> c2;
                int cinx1 = hmap[c1];
                int cinx2 = hmap[c2];
            //    cout << c1 << "-" << c2 << " = " << cinx1 << " - " << cinx2 << endl;
                clearRuntime(ccnt);
                cout << find_shortest_path(cinx1, cinx2) << endl;
            }
            getchar();
            getchar(); // should return 0xA (enter)
        }
    
        return 0;
    }
    View Code
  • 相关阅读:
    使用socket BPF/Linux内核工程导论——网络:Filter(LSF、BPF、eBPF)
    使用Iperf工具测试android系统网络wifi的吞吐量wifithrougput
    html input中 button和submit的区别
    Linux转发性能评估与优化(转发瓶颈分析与解决方案)
    交叉编译器 arm-linux-gnueabi 和 arm-linux-gnueabihf 的区别
    MySQL查询不区分大小写的sql写法
    Docker镜像保存save、加载load
    将Spring-boot应用部署到Docker容器
    Docker 安装使用
    Scalatra文件下载时中文乱码
  • 原文地址:https://www.cnblogs.com/tonix/p/3548072.html
Copyright © 2011-2022 走看看