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  • LeetCode "Word Pattern II"

    Here is the mind flow: we don't know 1st token right? then we try it one by one - recursively.

    typedef unordered_map<string, string> HMap;
    class Solution {
        bool go(string pattern, string str, HMap p2s)
        {
            size_t plen = pattern.length();
            size_t slen = str.length();
            if(!plen) return !slen;
            if(plen > slen) return false;
    
            string c = pattern.substr(0, 1);
            string npat = pattern.substr(1);
            for(int sl = 1; sl <= slen; sl ++)
            {
                string tk = str.substr(0, sl);
                string nstr = str.substr(sl);
                if(p2s.count(c))
                {
                    if(p2s[c] == tk)
                    {
                        if(go(npat, nstr, p2s))
                            return true;
                    }
                }
                else
                {
                    HMap np2s = p2s;
                    np2s[c] = tk;
                    if(go(npat, nstr, np2s))
                        return true;
                }
            }
            return false;
        }
    public:
        bool wordPatternMatch(string pattern, string str) {
            size_t plen = pattern.length();
            size_t slen = str.length();
            if(plen == 0) return slen == 0;
            if(plen == 1) return slen > 0;
            if(plen > slen) return false;
    
            string c = pattern.substr(0, 1);
            string npat = pattern.substr(1);
    
            for(int sl = 1; sl <= slen; sl ++)
            {
                string head = str.substr(0, sl);
                HMap p2s; p2s[c] = head;
    
                string nstr = str.substr(sl);
                if(go(npat, nstr, p2s))
                    return true;
            }
            return false;
        }
    };
    View Code
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  • 原文地址:https://www.cnblogs.com/tonix/p/4866844.html
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