zoukankan      html  css  js  c++  java
  • 1118 Birds in Forest (25 分)

    Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in the forest, and for any pair of birds, tell if they are on the same tree.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains a positive number N (104​​) which is the number of pictures. Then N lines follow, each describes a picture in the format:

    B1​​ B2​​ ... BK​​

    where K is the number of birds in this picture, and Bi​​'s are the indices of birds. It is guaranteed that the birds in all the pictures are numbered continuously from 1 to some number that is no more than 104​​.

    After the pictures there is a positive number Q (104​​) which is the number of queries. Then Q lines follow, each contains the indices of two birds.

    Output Specification:

    For each test case, first output in a line the maximum possible number of trees and the number of birds. Then for each query, print in a line Yes if the two birds belong to the same tree, or No if not.

    Sample Input:

    4
    3 10 1 2
    2 3 4
    4 1 5 7 8
    3 9 6 4
    2
    10 5
    3 7
    

    Sample Output:

    2 10
    Yes
    No
    
     
    #include <bits/stdc++.h>
    using namespace std;
    int p[10010];
    int visit[10010];
    int a[10010];
    int n,m,k;
    int found(int a)
    {
        if(a==p[a]){
            return a;
        }
        return p[a]=found(p[a]);
    }
    void unite(int a,int b)
    {
        int x = found(a);
        int y = found(b);
        if(x!=y){
            p[x] = y;
        }
        return ;
    }
    bool istrue(int a,int b){
        return found(a) == found(b);
    }
    int main()
    {
        int x,y;
        set<int> s;
    
        for(int i=1;i<=10010;i++){
            p[i] = i;
        }
        scanf("%d",&n);
        for(int i=1;i<=n;i++){
            scanf("%d",&m);
            for(int j=1;j<=m;j++)
            {
                scanf("%d",&a[j]);
                s.insert(a[j]);
            }
            for(int j=2;j<=m;j++)
            {
                unite(a[j-1],a[j]);
            }
        }
        int sum = s.size();
        set<int> ss;
        for(int i=1;i<=sum;i++)
        {
            ss.insert(found(i));
        }
        cout<<ss.size()<<" "<<sum<<endl;
        scanf("%d",&k);
        while(k--)
        {
            scanf("%d%d",&x,&y);
            if(istrue(x,y)){
                cout<<"Yes"<<endl;
            }else{
                cout<<"No"<<endl;
            }
        }
        return 0;
    }
  • 相关阅读:
    mysql的存储过程与事务入门
    关于CreateProcess函数一些经验
    windows下dump文件调试
    指针相关
    nsi脚本中执行.bat文件要隐藏dos窗口问题
    C 预处理
    __declspec(dllimport)与__declspec(dllexport)作用总结
    [转]window下使用SetUnhandledExceptionFilter捕获让程序的崩溃
    字符集与编码[转]
    vc下项目的头文件包含目录以及库导入预计库目录设置
  • 原文地址:https://www.cnblogs.com/tonyyy/p/10545377.html
Copyright © 2011-2022 走看看