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  • 麻将算法(1)发牌数据分析

    void Shuffle(int *Pai)
    {
        int i;
        srand((unsigned)time(NULL));
    /*
    *    条筒万,每种四组,每组9张,共计108张
    *    00,01,02,03,04,05,06,07,08     (1-9)     
    *    00,01,02,03,04,05,06,07,08
    *    00,01,02,03,04,05,06,07,08
    *    00,01,02,03,04,05,06,07,08
    *     
    *    10,11,12,13,14,15,16,17,18
    *    10,11,12,13,14,15,16,17,18
    *    10,11,12,13,14,15,16,17,18
    *    10,11,12,13,14,15,16,17,18
    *    
    *    20,21,22,23,24,25,26,27,28
    *    20,21,22,23,24,25,26,27,28
    *    20,21,22,23,24,25,26,27,28
    *    20,21,22,23,24,25,26,27,28
    */
        for(i=0; i<108; i++)
        {
            Pai[i] = i/36*10 + i%9;
        }
        // 顺序打乱 
        for(i=0; i<108; i++)
        {
            swap(Pai[i], Pai[rand()%108]);    
        }    
    }

    01,11,21 十位数区分各个色牌, 个位区分各牌的值 : 

    依此 读 一条,一筒,一万;

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  • 原文地址:https://www.cnblogs.com/toolbear/p/2954035.html
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