10道题目，A了4道，5道会做，5道不会，果然渣渣。。。
这次测验感觉无限段错误。。
最近写题段错误出现的比较多，问题主要在于：
1.命名一个变量未初始化，而之后的语句又恰好未赋值，并且使用
2.开超大数组一定不要开在函数里面！！！！
3.无限循环
4.scanf("%d",&x)少了＆有时候也会出现
一个是初始化的问题，还一个建树的过程出错，但还不知道错在哪里。先附上几道没A的题， 以后慢慢解决。
Description
Fox Ciel is going to publish a paper on FOCS (Foxes Operated Computer Systems, pronounce: "Fox"). She heard a rumor: the authors list on the paper is always sorted in the lexicographical order.
After checking some examples, she found out that sometimes it wasn't true. On some papers authors' names weren't sorted in lexicographical order in normal sense. But it was always true that after some modification of the order of letters in alphabet, the order of authors becomes lexicographical!
She wants to know, if there exists an order of letters in Latin alphabet such that the names on the paper she is submitting are following in the lexicographical order. If so, you should find out any such order.
Lexicographical order is defined in following way. When we compare s and t, first we find the leftmost position with differing characters: si ≠ ti. If there is no such position (i. e. s is a prefix of t or vice versa) the shortest string is less. Otherwise, we compare characters si and ti according to their order in alphabet.
Input
The first line contains an integer n (1 ≤ n ≤ 100): number of names.
Each of the following n lines contain one string namei (1 ≤ |namei| ≤ 100), the i-th name. Each name contains only lowercase Latin letters. All names are different.
Output
If there exists such order of letters that the given names are sorted lexicographically, output any such order as a permutation of characters 'a'–'z' (i. e. first output the first letter of the modified alphabet, then the second, and so on).
Otherwise output a single word "Impossible" (without quotes).
Sample Input
3
rivest
shamir
adleman
bcdefghijklmnopqrsatuvwxyz
10
tourist
petr
wjmzbmr
yeputons
vepifanov
scottwu
oooooooooooooooo
subscriber
rowdark
tankengineer
Impossible
10
petr
egor
endagorion
feferivan
ilovetanyaromanova
kostka
dmitriyh
maratsnowbear
bredorjaguarturnik
cgyforever
aghjlnopefikdmbcqrstuvwxyz
7
car
care
careful
carefully
becarefuldontforgetsomething
otherwiseyouwillbehacked
goodluck
acbdefhijklmnogpqrstuvwxyz
Description
As Christmas is around the corner, Boys are busy in choosing christmas presents to send to their girlfriends. It is believed that chain bracelet is a good choice. However, Things are not always so simple, as is known to everyone, girl's fond of the colorful decoration to make bracelet appears vivid and lively, meanwhile they want to display their mature side as college students. after CC understands the girls demands, he intends to sell the chain bracelet called CharmBracelet. The CharmBracelet is made up with colorful pearls to show girls' lively, and the most important thing is that it must be connected by a cyclic chain which means the color of pearls are cyclic connected from the left to right. And the cyclic count must be more than one. If you connect the leftmost pearl and the rightmost pearl of such chain, you can make a CharmBracelet. Just like the pictrue below, this CharmBracelet's cycle is 9 and its cyclic count is 2:
Now CC has brought in some ordinary bracelet chains, he wants to buy minimum number of pearls to make CharmBracelets so that he can save more money. but when remaking the bracelet, he can only add color pearls to the left end and right end of the chain, that is to say, adding to the middle is forbidden.
CC is satisfied with his ideas and ask you for help.
Input
Each test case contains only one line describe the original ordinary chain to be remade. Each character in the string stands for one pearl and there are 26 kinds of pearls being described by 'a' ~'z' characters. The length of the string Len: ( 3 <= Len <= 100000 ).
Output
Sample Input
Sample Output
Description
Consider the English alphabet {a,b,c,...,z}. Using this alphabet, a set of valid words are to be formed that are in a strict lexicographic order. In this set of valid words, the successive letters of a word are in a strictly ascending order; that is, later letters in a valid word are always after previous letters with respect to their positions in the alphabet list {a,b,c,...,z}. For example,
abc aep gwz
are all valid three-letter words, whereas
aab are cat
are not.
For each valid word associate an integer which gives the position of the word in the alphabetized list of words. That is:
a -> 1
b -> 2
.
.
z -> 26
ab -> 27
ac -> 28
.
.
az -> 51
bc -> 52
.
.
vwxyz -> 83681
Your program is to read a series of input lines. Each input line will have a single word on it, that will be from one to five letters long. For each word read, if the word is invalid give the number 0. If the word read is valid, give the word's position index in the above alphabetical list.
Input
The input will be terminated by end-of-file.
Output
Sample Input
z a cat vwxyz
Sample Output
26 1 0 83681
Description
为了方便起见，我们把所有的物品从1开始进行编号，酋长的允诺也看作一个物品，并且编号总是1。每个物品都有对应的价格P，主人的 地位等级L，以及一系列的替代品Ti和该替代品所对应的"优惠"Vi。如果两人地位等级差距超过了M，就不能"间接交易"。你必须根据这些数据来计算出探 险家最少需要多少金币才能娶到酋长的女儿。
Input
Output
Sample Input
1 4 10000 3 2 2 8000 3 5000 1000 2 1 4 200 3000 2 1 4 200 50 2 0
Sample Output
5250
Description
Besides,X ij meets the following conditions:
1.X 12+X 13+...X 1n=1
2.X 1n+X 2n+...X n-1n=1
3.for each i (1<i<n), satisfies ∑X ki (1<=k<=n)=∑X ij (1<=j<=n).
For example, if n=4,we can get the following equality:
X 12+X 13+X 14=1
X 14+X 24+X 34=1
X 12+X 22+X 32+X 42=X 21+X 22+X 23+X 24
X 13+X 23+X 33+X 43=X 31+X 32+X 33+X 34
Now ,we want to know the minimum of ∑C ij*X ij(1<=i,j<=n) you can get.
For sample, X 12=X 24=1,all other X ij is 0.
Input
For each test case ,the first line contains one integer n (1<n<=300).
The next n lines, for each lines, each of which contains n integers, illustrating the matrix C, The j-th integer on i-th line is C ij(0<=C ij<=100000).
Output
Sample Input
Sample Output
Hint
12
For sample, X
=X24
=1,all other Xij
is 0.
Description
假设有n个人按顺序站在他的面前，他们的身高分别是h[1], h[2] ... h[n]，吉哥希望从中挑出一些人，让这些人形成一个新的队形，新的队形若满足以下三点要求，则就是新的完美队形：
1、挑出的人保持原队形的相对顺序不变，且必须都是在原队形中连续的；
2、左右对称，假设有m个人形成新的队形，则第1个人和第m个人身高相同，第2个人和第m-1个人身高相同，依此类推，当然如果m是奇数，中间那个人可以任意；
3、从左到中间那个人，身高需保证不下降，如果用H表示新队形的高度，则H[1] <= H[2] <= H[3] .... <= H[mid]。
现在吉哥想知道：最多能选出多少人组成新的完美队形呢？
Input
每组数据首先是一个整数n(1 <= n <= 100000)，表示原先队形的人数，接下来一行输入n个整数，表示原队形从左到右站的人的身高（50 <= h <= 250，不排除特别矮小和高大的）。
Output
Sample Input
Sample Output
//此题可以直接用MARACHER算法来做，但不知道为什么老是超时，还可以将原数列翻转过来，再求LCIS #include<iostream> #include<cstdio> #include<cstring> using namespace std; const int N=220; int n,a[N],b[N],dp[N]; int main(){ //freopen("input.txt","r",stdin); int t; scanf("%d",&t); while(t--){ scanf("%d",&n); for(int i=1;i<=n;i++){ scanf("%d",&a[i]); b[n+1-i]=a[i]; } memset(dp,0,sizeof(dp)); int len,ans=1; for(int i=1;i<=n;i++){ len=0; for(int j=1;j<=(n-i+1);j++){ //j<=n-i+1 保证最多中间只重复一人 if(a[i]>b[j]) len=max(len,dp[j]); else if(a[i]==b[j]) dp[j]=max(dp[j],len+1); if(i<(n+1-j)) //判断是否重叠 ans=max(ans,dp[j]*2); else ans=max(ans,dp[j]*2-1); } } printf("%d ",ans); } return 0; }