http://codeforces.com/contest/500/problem/D
https://blog.csdn.net/ShiAokai/article/details/42921885?locationNum=8&fps=1
1 import java.util.ArrayList; 2 import java.util.Scanner; 3 4 public class Main { 5 6 static int n; 7 static long[] cnt = new long[(int) (1e5 + 50)]; 8 static ArrayList<Edge>[] road = new ArrayList[(int) (1e5 + 50)]; 9 10 static int dfs(int x, int fa) { 11 int child = 1; 12 for (int i = 0, c, y; i < road[x].size(); i++) { 13 y = road[x].get(i).y; 14 if (y == fa) continue; 15 c = dfs(y, x); 16 child += c; 17 cnt[road[x].get(i).id] = 1L * c * (n - c); 18 } 19 return child; 20 } 21 22 public static void main(String[] args) { 23 Scanner io = new Scanner(System.in); 24 n = io.nextInt(); 25 for (int i = 0; i < road.length; i++) road[i] = new ArrayList<>(); 26 int[] len = new int[n + 1]; 27 28 for (int i = 1, x, y; i <= n - 1; i++) { 29 x = io.nextInt(); 30 y = io.nextInt(); 31 len[i] = io.nextInt(); 32 road[x].add(new Edge(y, i)); 33 road[y].add(new Edge(x, i)); 34 } 35 36 dfs(1, -1); 37 double sum = 0; 38 for (int i = 1; i <= n - 1; i++) sum += cnt[i] * len[i]; 39 int q = io.nextInt(); 40 for (int i = 0, id2, len2; i < q; i++) { 41 id2 = io.nextInt(); 42 len2 = io.nextInt(); 43 sum -= cnt[id2] * (len[id2] - len2); 44 len[id2] = len2; 45 //什么时候检测到double就什么时候升double 46 //()会改变检测顺序,所以下面的1.0如果没有就会溢出 47 System.out.println((sum * 6) / (1.0 * (n - 1) * n)); 48 } 49 } 50 51 static class Edge { 52 int y, id; 53 54 public Edge(int y, int id) { 55 this.y = y; 56 this.id = id; 57 } 58 } 59 60 }