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  • C++练习 | 运算符重载练习

    #include <iostream>
    #include <cmath>
    #include <cstring>
    #include <iomanip>
    using namespace std;
    
    int gcd(int x,int y)
    {
        x=abs(x);
        y=abs(y);
        if(x<y)
        {
            int t=x;
            x=y;
            y=t;
        }
        if(x%y==0)
            return y;
        else
            return gcd(x%y,y);
    }
    
    class Rational
    {
    private:
        int z;    //分子
        int m;    //分母
    public:
        Rational(int a=0, int b=1)//构造有理数分数,分子默认为0,分母默认为1
        {
            z=a;
            m=b;
        }
        friend Rational& yuefen(Rational& r)//约分函数对分数化简
        {
            int c;
            c=gcd(r.z,r.m);
            r.z=r.z/c;
            r.m=r.m/c;
            if(r.z>0&&r.m<0)
            {
                r.z=0-r.z;
                r.m=0-r.m;
            }
            if(r.z<0&&r.m<0)
            {
                r.z=abs(r.z);
                r.m=abs(r.m);
            }
            return r;
        }
        friend Rational operator+(const Rational &r1, const Rational &r2)
        {
            Rational t;
            t.m=r1.m*r2.m;
            t.z=r1.z*r2.m+r2.z*r1.m;
            return t;
        }
        friend Rational operator-(const Rational &r1, const Rational &r2)
        {
            Rational t;
            t.m=r1.m*r2.m;
            t.z=r1.z*r2.m-r2.z*r1.m;
            return t;
        }
        friend Rational operator*(const Rational &r1, const Rational &r2)
        {
            Rational t;
            t.m=r1.m*r2.m;
            t.z=r1.z*r2.z;
            return t;
        }
        friend Rational operator/(const Rational &r1, const Rational &r2)
        {
            Rational t;
            t.m=r1.m*r2.z;
            t.z=r1.z*r2.m;
            return t;
        }
        Rational & operator+=(const Rational &r)
        {
            Rational t;
            t.m=this->m*r.m;
            t.z=this->z*r.m+r.z*this->m;
            this->z=t.z;
            this->m=t.m;
            return *this;
        }
        Rational & operator-=(const Rational &r)
        {
            Rational t;
            t.m=this->m*r.m;
            t.z=this->z*r.m-r.z*this->m;
            this->m=t.m;
            this->z=t.z;
            return *this;
        }
        Rational & operator*=(const Rational &r)
        {
            this->m=this->m*r.m;
            this->z=this->z*r.z;
            return *this;
        }
        Rational & operator/=(const Rational &r)
        {
            Rational t;
            t.m=this->m*r.z;
            t.z=this->z*r.m;
            this->m=t.m;
            this->z=t.z;
            return *this;
        }
        friend bool operator==(const Rational &s1, const Rational &s2)//判断两个有理数是否相等
        {
            int m1,m2,z1,z2,t1,t2;
            t1=gcd(s1.z,s1.m);
            t2=gcd(s2.z,s2.m);
            m1=s1.m/t1;
            m2=s2.m/t2;
            z1=s1.z/t1;
            z2=s1.z/t2;
            if(m1==m2&&z1==z2)
                return 1;
            else
                return 0;
        }
        friend bool operator!=(const Rational &s1, const Rational &s2)//判断两个有理数是否不等
        {
            int m1,m2,z1,z2,t1,t2;
            t1=gcd(s1.z,s1.m);
            t2=gcd(s2.z,s2.m);
            m1=s1.m/t1;
            m2=s2.m/t2;
            z1=s1.z/t1;
            z2=s1.z/t2;
            if(m1==m2&&z1==z2)
                return 0;
            else
                return 1;
        }
        friend ostream & operator<<(ostream &t1, const Rational &t2)
        {
            t1<<t2.z<<"/"<<t2.m;
            return t1;
        }
        friend istream & operator>>(istream &t1, Rational &t2)
        {
            t1>>t2.z>>t2.m;
            return t1;
        }
    };
    
    int main()
    {
        Rational r1,r2,r3;
        while(cin>>r1>>r2)
        {
            cout << "r1 = " << yuefen(r1) << "
    " << "r2 = " << yuefen(r2) << endl;
            r3 = r1 + r2;
            cout << "r1+r2 = " << yuefen(r3) << endl;
            r3 = r1 - r2;
            cout << "r1-r2 = " << yuefen(r3) << endl;
            r3 = r1 * r2;
            cout << "r1*r2 = " << yuefen(r3) << endl;
            r3 = r1 / r2;
            cout << "r1/r2 = " << yuefen(r3) << endl;
            cout << (r1 == r2) << " " << (r1 != r2) << endl;
            cout << yuefen(r1 += r2) << endl;
            cout << yuefen(r1 -= r2) << endl;
            cout << yuefen(r1 *= r2) << endl;
            cout << yuefen(r1 /= r2) << endl;
        }
        return 0;
        
    }
    #include <iostream>
    #include <cmath>
    #include <cstring>
    #include <iomanip>
    using namespace std;
    
    class CheckedPtr
    {
    public:
        CheckedPtr(int * b, int * e):beg(b), end(e), curr(b){  }
        CheckedPtr & operator ++()// prefix ++
        {
            this->curr+=1;
            return *this;
        }
        CheckedPtr & operator --() // prefix --
        {
            this->curr-=1;
            return *this;
        }
        CheckedPtr   operator ++(int)// postfix ++,()内int用于c区分前置后置
        {
            CheckedPtr t=*this;
            this->curr+=1;
            return t;
        }
        CheckedPtr   operator --(int)// postfix --
        {
            CheckedPtr t=*this;
            this->curr-=1;
            return t;
        }
        int * GetBeg()
        {
            return beg;
        }
        int * GetEnd()
        {
            return end;
        }
        int * GetCurr()
        {
            return curr;
        }
    private:
        int * beg;  // pointer to beginning of the array
        int * end;  // one past the end of the array
        int * curr; // current position within the array
    };
    
    int main()
    {
        int array[10] = {1,2,3,4,5,6,7,8,9,10};
        CheckedPtr cp(array, array+10);
        for(;cp.GetCurr()<cp.GetEnd();cp++)
            cout<<*cp.GetCurr()<<" ";
        cout<<endl;
        for(--cp;cp.GetCurr()>cp.GetBeg();cp--)
            cout<<*cp.GetCurr()<<" ";
        cout<<*cp.GetCurr()<<endl;
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/tsj816523/p/10669124.html
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