zoukankan      html  css  js  c++  java
  • A1083 List Grades (25 分)

    Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

    Input Specification:
    Each input file contains one test case. Each case is given in the following format:

    N
    name[1] ID[1] grade[1]
    name[2] ID[2] grade[2]
    ... ...
    name[N] ID[N] grade[N]
    grade1 grade2
    where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

    Output Specification:
    For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.

    Sample Input 1:
    4
    Tom CS000001 59
    Joe Math990112 89
    Mike CS991301 100
    Mary EE990830 95
    60 100
    Sample Output 1:
    Mike CS991301
    Mary EE990830
    Joe Math990112
    Sample Input 2:
    2
    Jean AA980920 60
    Ann CS01 80
    90 95
    Sample Output 2:
    NONE

    开始技术总结:

    • 第一点就是初始化数组或是结构体的时候,大小要用常量,不能够使用输入量初始化

    • 还有就是中文的括号注意一点

    • 参考代码:

    #define _CRT_SECURE_NO_WARNINGS
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    const int MAXN = 50;
    struct Student {
    	char ID[11];
    	char name[11];
    	int grade;
    }student[MAXN];
    
    bool cmp(Student a, Student b) {
    	if (a.grade != b.grade) return a.grade > b.grade;
    }
    
    int main(){
    
    	int grade1, grade2;
    	int N;
    	scanf("%d", &N);
    	for (int i = 0; i < N; i++) {
    		scanf("%s%s%d", student[i].name, student[i].ID, &student[i].grade);
    	}
    	scanf("%d%d", &grade1, &grade2);
    	sort(student, student + N, cmp);
    	int flag = 0;//用来标记是否又符合条件的同学,0表示没有
    	for (int j = 0; j < N; j++) {
    		if (student[j].grade <= grade2 && student[j].grade >= grade1) {
    			printf("%s %s
    ", student[j].name, student[j].ID);
    			flag = 1;
    		}
    	}
    	if (flag == 0) {
    		printf("NONE");
    	}
    	system("pause");
    	return 0;
    }
    
    作者:睿晞
    身处这个阶段的时候,一定要好好珍惜,这是我们唯一能做的,求学,钻研,为人,处事,交友……无一不是如此。
    劝君莫惜金缕衣,劝君惜取少年时。花开堪折直须折,莫待无花空折枝。
    曾有一个业界大牛说过这样一段话,送给大家:   “华人在计算机视觉领域的研究水平越来越高,这是非常振奋人心的事。我们中国错过了工业革命,错过了电气革命,信息革命也只是跟随状态。但人工智能的革命,我们跟世界上的领先国家是并肩往前跑的。能身处这个时代浪潮之中,做一番伟大的事业,经常激动的夜不能寐。”
    本文版权归作者和博客园共有,欢迎转载,但未经作者同意必须保留此段声明,且在文章页面明显位置给出原文连接,否则保留追究法律责任的权利.
  • 相关阅读:
    poj3348 Cow
    poj3348 Cow
    日常。。。强行续
    日常。。。又又续
    日常。。。又又续
    日常。。。又续
    内存检索
    MyLayer MyScene
    冒泡排序
    Array数组的排序与二分查字法
  • 原文地址:https://www.cnblogs.com/tsruixi/p/11553140.html
Copyright © 2011-2022 走看看