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  • jquery遍历一个数组

    <!DOCTYPE html>
    <html>
    <head>
        <meta charset="UTF-8">
        <title></title>
    </head>
    <body>
    <script src="http://www.lcqjgj.com/static/home/js/jquery-3.3.1.min.js"></script>
    <ul id="ull">
        <li data-uid="aaa">1</li>
        <li data-uid="bbb">2</li>
        <li data-uid="ccc">3</li>
        <li data-uid="ddd">4</li>
        <li data-uid="eee">5</li>
        <li data-uid="bbb">2</li>
        <li data-uid="ccc">3</li>
        <li data-uid="ddd">4</li>
        <li data-uid="eee">5</li>
    
    </ul>
    
    <script>
        var sss = ["aaa","bbb","ccc","ddd","eee"];
        var bg = ["#5a98de","#3bb4f2","#429842","#c85e0b","#c62b26"];
    
        for(var i = 0; i < sss.length; i++){
            var qwer = sss[i];
            var asdf = bg[i];
            // qqq = sss[i];
            $("li[data-uid="+qwer+"]").css('background',asdf);
        }
    
    </script>
    </body>
    </html>
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  • 原文地址:https://www.cnblogs.com/tytsp/p/9674865.html
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