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  • Product of Polynomials

    题意:多项式相乘,合并同类项后输出每一项的系数。

    题目链接:https://www.patest.cn/contests/pat-a-practise/1009

    分析:注意合并后系数为0,这一项就不存在了。

    #include<bits/stdc++.h>
    using namespace std;
    const int MAXN = 1000 + 10;
    const int MAXT = 2000 + 10;
    map<int, double> mp1;
    map<int, double> mp2;
    map<int, double> mp3;
    stack<pair<int, double> > st;
    int main(){
        int n;
        scanf("%d", &n);
        int id;
        double x;
        while(n--){
            scanf("%d%lf", &id, &x);
            mp1[id] = x;
        }
        scanf("%d", &n);
        while(n--){
            scanf("%d%lf", &id, &x);
            mp2[id] = x;
        }
        for(map<int, double>::iterator it1 = mp1.begin(); it1 != mp1.end(); ++it1){
            for(map<int, double>::iterator it2 = mp2.begin(); it2 != mp2.end(); ++it2){
                id = (*it1).first + (*it2).first;
                mp3[id] += (*it1).second * (*it2).second;
            }
        }
        for(map<int, double>::iterator it = mp3.begin(); it != mp3.end(); ++it){
            if((*it).second == 0) continue;
            st.push(pair<int, double>((*it).first, (*it).second));
        }
        printf("%d", st.size());
        while(!st.empty()){
            pair<int, double> tmp = st.top();
            st.pop();
            printf(" %d %.1lf", tmp.first, tmp.second);
        }
        printf("
    ");
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/tyty-Somnuspoppy/p/8488929.html
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