zoukankan      html  css  js  c++  java
  • 紫书第三章训练 UVA 1585 Score by 16 BobHuang

    There is an objective test result such as ``OOXXOXXOOO". An `O' means a correct answer of a problem and an `X' means a wrong answer. The score of each problem of this test is calculated by itself and its just previous consecutive `O's only when the answer is correct. For example, the score of the 10th problem is 3 that is obtained by itself and its two previous consecutive `O's.

    Therefore, the score of ``OOXXOXXOOO" is 10 which is calculated by ``1+2+0+0+1+0+0+1+2+3".

    You are to write a program calculating the scores of test results.

    Input

    Your program is to read from standard input. The input consists of T test cases. The number of test cases T is given in the first line of the input. Each test case starts with a line containing a string composed by `O' and `X' and the length of the string is more than 0 and less than 80. There is no spaces between `O' and `X'.

    Output

    Your program is to write to standard output. Print exactly one line for each test case. The line is to contain the score of the test case.

    The following shows sample input and output for five test cases.

    Sample Input

    5 
    OOXXOXXOOO 
    OOXXOOXXOO 
    OXOXOXOXOXOXOX 
    OOOOOOOOOO 
    OOOOXOOOOXOOOOX

    Sample Output

    10 
    9 
    7 
    55 
    30
    这个就更简单了,题都没怎么看直接看的样例,看到了这句话"the score of ``OOXXOXXOOO" is 10 which is calculated by ``1+2+0+0+1+0+0+1+2+3".",
    心里就更踏实了,对一个加一分,连对几个加几分。
     1 #include<stdio.h>
     2 int main()
     3 {   int t;
     4     scanf ("%d", &t);
     5     getchar();
     6     while (t--)
     7     {   char s[105];
     8         gets(s);
     9         int a=0,sum=0;
    10         for(int i=0;s[i];i++){
    11             if(s[i]=='O'){
    12                 a++;
    13                 sum+=a;}
    14             else a=0;
    15          }
    16          printf("%d
    ",sum);
    17     }
    18     return 0;
    19 }
  • 相关阅读:
    2012个人总结与展望
    C++Event机制的简单实现
    string与char*比较 ——why use string
    创建型模式学习总结——设计模式学习笔记
    Bridge模式——设计模式学习笔记
    Singleton模式——设计模式学习
    Adapter模式——设计模式学习笔记
    C++ 申请连续的对象内存
    7 个致命的 Linux 命令与个人评论
    关于保存Activity的状态
  • 原文地址:https://www.cnblogs.com/tzcacm/p/6801468.html
Copyright © 2011-2022 走看看