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  • 快慢指针算法-单链表最后N个节点

        static class Node {
            private Node next;
            private int val;
    
            public Node(Node next, int val) {
                this.next = next;
                this.val = val;
            }
    
            public Node getNext() {
                return next;
            }
    
            public void setNext(Node next) {
                this.next = next;
            }
    
            public int getVal() {
                return val;
            }
    
            public void setVal(int val) {
                this.val = val;
            }
    
            @Override
            public boolean equals(Object o) {
                if (this == o) return true;
                if (o == null || getClass() != o.getClass()) return false;
                Node node = (Node) o;
                return val == node.val &&
                        Objects.equals(next, node.next);
            }
        }
    
        public static void main(String[] args) {
            Node node1 = new Node(null, 1);
            Node node2 = new Node(node1, 2);
            Node node3 = new Node(node2, 3);
            Node node4 = new Node(node3, 4);
            Node node5 = new Node(node4, 5);
            Node node6 = new Node(node5, 6);
            Node node7 = new Node(node6, 7);
            Node node8 = new Node(node7, 8);
            Node tail = new Node(node8, 9);
    
            int n = 2;
            Node slow = tail;
            //fast先走N步,然后slow与fast同时走
            Node fast = tail;
            for (int i = 0; i < n; i++) {
                fast = fast.next;
            }
            while (fast.next != null) {
                fast = fast.next;
                slow = slow.next;
            }
            System.out.println(slow.val);
        }
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  • 原文地址:https://www.cnblogs.com/use-D/p/13296805.html
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