zoukankan      html  css  js  c++  java
  • 二叉树的深度

    ##题目描述 输入一棵二叉树,求该树的深度。从根结点到叶结点依次经过的结点(含根、叶结点)形成树的一条路径,最长路径的长度为树的深度。

    思路

    时间复杂度O(lgn),空间复杂度O(lgn)。

    递归代码

    /**
    public class TreeNode {
        int val = 0;
        TreeNode left = null;
        TreeNode right = null;
    
        public TreeNode(int val) {
            this.val = val;
    
        }
    
    }
    */
    public class Solution {
        public int TreeDepth(TreeNode root) {
            if(root == null)    return 0;
            return Math.max(1+TreeDepth(root.left), 1+TreeDepth(root.right));
        }
    }
    

    非递归代码

    import java.util.Queue;
    import java.util.LinkedList;
    /**
    public class TreeNode {
        int val = 0;
        TreeNode left = null;
        TreeNode right = null;
    
        public TreeNode(int val) {
            this.val = val;
    
        }
    
    }
    */
    public class Solution {
        public int TreeDepth(TreeNode root) {
            if(root == null)    return 0;
            int count = 0;
            int width = 1;
            int depth = 0;
            TreeNode curr = null;
            Queue<TreeNode> queue = new LinkedList<TreeNode>();
            queue.offer(root);
            while(queue.size() != 0) {
                curr = queue.poll();
                if(curr.left != null) {
                    queue.offer(curr.left);
                }
                if(curr.right != null) {
                    queue.offer(curr.right);
                }
                count++;
                if(count == width) {
                    depth++;
                    count = 0;
                    width = queue.size();
                }
            }
            return depth;
        }
    }
    
  • 相关阅读:
    字体
    abstract关键词
    final关键词
    多态
    接口
    java面向对象
    java运算符
    JDK安装
    循环
    TextView控件
  • 原文地址:https://www.cnblogs.com/ustca/p/12361927.html
Copyright © 2011-2022 走看看