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  • Search a 2D Matrix

    Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

    • Integers in each row are sorted from left to right.
    • The first integer of each row is greater than the last integer of the previous row.

    For example,

    Consider the following matrix:

    [
      [1,   3,  5,  7],
      [10, 11, 16, 20],
      [23, 30, 34, 50]
    ]
    

    Given target = 3, return true.

    class Solution {
    public:
        bool searchMatrix(vector<vector<int> > &matrix, int target) {
            if(target<matrix[0][0])
                return false;
            int row    = matrix.size();
            int column = matrix[0].size();
            if(target>matrix[row-1][column-1])
                return false;
             int i,j;
             
            if(row==1)
         {       for(j=0;j<column;j++)
                {
                    if(target==matrix[0][j])
                        return true;
                }
                return false;
        }
           
            for(i=0;i<row;i++)
            {
                if(target<matrix[i][0])
                    {
                        for(j=0;j<column;j++)
                        {
                            if(target==matrix[i-1][j])
                                return true;
                        }
                        return false;
                    }
            }
             for(j=0;j<column;j++)
                 {
                    if(target==matrix[row-1][j])
                        return true;
                 }
                        return false;
        }
    };


    每天早上叫醒你的不是闹钟,而是心中的梦~
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  • 原文地址:https://www.cnblogs.com/vintion/p/4116970.html
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