Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
For example,
Consider the following matrix:
[ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50] ]
Given target = 3
, return true
.
class Solution { public: bool searchMatrix(vector<vector<int> > &matrix, int target) { if(target<matrix[0][0]) return false; int row = matrix.size(); int column = matrix[0].size(); if(target>matrix[row-1][column-1]) return false; int i,j; if(row==1) { for(j=0;j<column;j++) { if(target==matrix[0][j]) return true; } return false; } for(i=0;i<row;i++) { if(target<matrix[i][0]) { for(j=0;j<column;j++) { if(target==matrix[i-1][j]) return true; } return false; } } for(j=0;j<column;j++) { if(target==matrix[row-1][j]) return true; } return false; } };