Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
一次AC平衡二叉树, 左右子树都是, 且深度差在1之内
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int depthTree(TreeNode *root) { if(!root) return 0; if(!root->left&&!root->right) return 1; else return 1 + max(depthTree(root->left), depthTree(root->right)); } bool isBalanced(TreeNode *root) { if(!root) return true; int diff_depth = depthTree(root->left) - depthTree(root->right); if(isBalanced(root->left)&&isBalanced(root->right)&&diff_depth>=-1&&diff_depth<=1) return true; return false; } };