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  • C.char字符串的拼接和const char*的转换

    C里没有String类型

    要用char[]来代替String的职能

    上代码:

     1 #include <stdio.h>
     2 #include <string.h>
     3 
     4 int main(void)
     5 {
     6     const char *p1;
     7     char str1[] = "hello";
     8     char str2[] = " world";
     9     char newStr[50] = "";
    10     strcat(newStr, "good,"); //直接把字符串添加到newStr
    11     strcat(newStr, str1);    //str1添(追)加到newStr
    12     strcat(newStr, str2);    //str2添(追)加到newStr
    13     p1 = newStr;             //char可以直接赋值给const char*
    14     printf("p1: %s
    ", p1);
    15     printf("p1.length(err): %d
    ", sizeof(p1)); //这个获取的长度并不是真实字符串长度
    16     printf("p1.length: %d
    ", getLength(p1));
    17     printf("str1.length: %d 
    ", sizeof(str1)); //(含字符串尾部的结束符,所以长度要加1)
    18     printf("str2.length: %d
    ", sizeof(str2));
    19     printf("newStr.length: %d 
    ", sizeof(newStr)); //(按实际定义的数组长度)
    20

    运行结果:

    p1: good,hello world
    p1.length(err): 8
    p1.length: 16
    str1.length: 6
    str2.length: 7
    newStr.length: 50
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  • 原文地址:https://www.cnblogs.com/visionsl/p/13600433.html
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