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  • mysql之子查询作业

    #数据准备
    drop table if exists class;
    create table class(
        class_no int(2) unsigned zerofill primary key auto_increment comment '班级编号',
        class_name varchar(30) not null comment '班级名称'
    );
    insert into class values(1, '培优班');
    insert into class values(2, '普通班');

    drop table if exists student;
    create table student(
        stu_no int(2) unsigned zerofill primary key auto_increment comment '学员编号',
        stu_name varchar(30) not null comment '学员姓名',
        stu_sex varchar(3) not null comment '学员性别',
        stu_age tinyint(2) unsigned zerofill comment '学员年代',
        grade double(5,2) zerofill comment '成绩',
        class_no int(2) unsigned zerofill comment '所在班级编号',
        foreign key(class_no) references class(class_no)
    );
    insert into student values(01, '李白', '男', 18, 60, 01);
    insert into student values(02, '杜甫', '男', 20, 76, 01);
    insert into student values(03, '张飞', '男', 32, 80, 02);
    insert into student values(04, '韩信', '男', 26, 98, 02);
    insert into student values(05, '了龙', '男', 27, 56, 02);
    insert into student values(06, '大乔', '女', 17, 88, 01);
    insert into student values(07, '小乔', '女', 16, 96, 01);
    insert into student values(08, '小乔', '女', 16, 90, 01);
    insert into student values(09, '关哥', '男', 32, 80, 02);
    insert into student values(10, '刘备', '男', 36, 98, null);
    alter table student drop foreign key `student_ibfk_1`;
    ***********************************************************************************************************************************
    // 班级为null表示不在任何一个班级,所以将班级为null的学生除外
    1: 查询出每一个班级的最低成绩分别是多少
    select class_no,min(grade) from student where (class_no is not null) group by class_no;

    2: 查询出每一个班级的人数是多少
    select class_no,count(*) from student where (class_no is not null) group by class_no;

    3: 查询出每一个班级的平均分是多少,需求是按平均分的降序排序
     select class_no,avg(grade) as avg from student  where(class_no is not null) group by class_no order by avg desc;

    4: 查询出每一个班级的男学员与女学员的平均分分别是多少,按照平均分的降序排序
    select class_no,stu_sex,avg(grade) as avg from student group by class_no,stu_sex order by avg desc;

    5: 查询出每一个班级学生的成绩在80到95的人数
    select class_no, count(*) from student where (class_no is not null) and (grade between 80 and 95) group by class_no;

    6: 查询出平均分小于80的班级
    select class_no,avggrade from (select class_no,avg(grade) as avggrade from student group by class_no) as temp where (class_no is not null) and avggrade < 80;(创建临时表)
    mysql> select class_no,avg(grade) as avg from student group by class_no having avg < 80;
    7: 查询出01号班级的平均成绩和02班级的总成绩(使用一条语句)---使用并和查询
    (select class_no,concat("平均成绩:",avg(grade)) as '成绩' from student where class_no  = 1) union (select class_no,concat("总成绩:",sum(grade)) as '成绩' from student where class_no  = 2);
       查询每个班级的平均成绩和总成绩:
    select class_no, avg(grade), sum(grade) from student where (class_no is not null) group by class_no;

    8: 查询出平均分最低的班级
     // 多个虚表
     //select class_no from (select class_no,avg(grade) as grade from student where (class_no is not null) group by class_no) as temp where grade = (select min(t1_grade) from (select avg(grade) as t1_grade from student group by class_no) as temp1);
    select class_no,avg(grade) from student group by class_no order by avg(grade) asc limit 1;
    select class_no,avg(grade) as avg from student group by class_no having avg = (select avg(grade) from student group by class_no order by avg(grade) asc limit 1);
    9: 查询出学号为4,8,9的学生
    select * from student where stu_no in (4,8,9);

    10: 查询出每一个班级中成绩小于平均分的学员
     select * from student,(select class_no as cno ,avg(grade) as agrade from student where (class_no is not null) group by class_no) as temp where grade < agrade and class_no = cno;





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  • 原文地址:https://www.cnblogs.com/wadmwz/p/7612604.html
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