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  • BZOJ1803: Spoj1487 Query on a tree III

    题解:主席树裸题    查询第K小出现的下标

    #include <algorithm>
    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <vector>
    #include <stack>
    #include <queue>
    #include <cmath>
    #include <set>
    #include <map>
    #define mp make_pair
    #define pb push_back
    #define pii pair<int,int>
    #define link(x) for(edge *j=h[x];j;j=j->next)
    #define inc(i,l,r) for(int i=l;i<=r;i++)
    #define dec(i,r,l) for(int i=r;i>=l;i--)
    const int MAXN=1e5+10;
    const int NM=2e3+10;
    const double eps=1e-8;
    #define ll long long
    using namespace std;
    struct edge{int t;edge*next;}e[MAXN<<1],*h[MAXN],*o=e;
    void add(int x,int y){o->t=y;o->next=h[x];h[x]=o++;}
    ll read(){
        ll x=0,f=1;char ch=getchar();
        while(!isdigit(ch)){if(ch=='-')f=-1;ch=getchar();}
        while(isdigit(ch))x=x*10+ch-'0',ch=getchar();
        return x*f;
    }
    int p[MAXN],cnt,a[MAXN],fp[MAXN],num[MAXN],rt[MAXN];
    vector<int>vec;
    int pos[MAXN];
    void dfs(int x,int fa){
    	p[x]=++cnt;fp[p[x]]=x;num[x]=1;
    	link(x){
    		if(j->t!=fa)dfs(j->t,x),num[x]+=num[j->t];
    	}
    }
    typedef struct node{
    	int l,r,sum;
    }node;
    node d[21*MAXN];
    void update(int &x,int y,int l,int r,int t){
    	x=++cnt;d[x]=d[y];d[x].sum++;
    	if(l==r)return ;
    	int mid=(l+r)>>1;
    	if(t<=mid)update(d[x].l,d[y].l,l,mid,t);
    	else update(d[x].r,d[y].r,mid+1,r,t);
    }
    int ans;
    void querty(int x,int y,int l,int r,int k){
    	if(l==r){ans=l;return ;}
    	int mid=(l+r)>>1;
    	int t=d[d[y].l].sum-d[d[x].l].sum;
    	if(k<=t)querty(d[x].l,d[y].l,l,mid,k);
    	else querty(d[x].r,d[y].r,mid+1,r,k-t);
    }
    int main(){
    	int n;n=read();
    	inc(i,1,n)a[i]=read(),vec.pb(a[i]);
    	sort(vec.begin(),vec.end());
    	int sz=unique(vec.begin(),vec.end())-vec.begin();
    	inc(i,1,n)a[i]=lower_bound(vec.begin(),vec.begin()+sz,a[i])-vec.begin()+1,pos[a[i]]=i;
    	int u,v;
    	inc(i,1,n-1)u=read(),v=read(),add(u,v),add(v,u);
    	dfs(1,0);
    	inc(i,1,n)update(rt[i],rt[i-1],1,sz,a[fp[i]]);
    	int m=read();
    	while(m--){
    		u=read();v=read();
    		querty(rt[p[u]-1],rt[p[u]+num[u]-1],1,sz,v);
    		printf("%d
    ",pos[ans]);
    	}
    }
     
    
    
     
    

    1803: Spoj1487 Query on a tree III

    Time Limit: 1 Sec  Memory Limit: 64 MB
    Submit: 760  Solved: 329
    [Submit][Status][Discuss]

    Description

    You are given a node-labeled rooted tree with n nodes. Define the query (x, k): Find the node whose label is k-th largest in the subtree of the node x. Assume no two nodes have the same labels.

    Input

    The first line contains one integer n (1 <= n <= 10^5). The next line contains n integers li (0 <= li <= 109) which denotes the label of the i-th node. Each line of the following n - 1 lines contains two integers u, v. They denote there is an edge between node u and node v. Node 1 is the root of the tree. The next line contains one integer m (1 <= m <= 10^4) which denotes the number of the queries. Each line of the next m contains two integers x, k. (k <= the total node number in the subtree of x)

    Output

    For each query (x, k), output the index of the node whose label is the k-th largest in the subtree of the node x.

    Sample Input

    5
    1 3 5 2 7
    1 2
    2 3
    1 4
    3 5
    4
    2 3
    4 1
    3 2
    3 2

    Sample Output


    5
    4
    5
    5
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  • 原文地址:https://www.cnblogs.com/wang9897/p/9739006.html
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