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  • hdu 3622 二分+2-SAT判定

    思路:如题

    #include<iostream>
    #include<algorithm>
    #include<cstring>
    #include<cstdio>
    #include<cmath>
    #define Maxm 100010
    #define eps 1e-4
    using namespace std;
    int vi[220],head[220],e,n,m,id[220],lab,num,dfn[220],low[220],Stack[220],top;
    double Max;
    struct Point{
        double x,y;
    }p[210];
    struct Edge{
        int u,v,next;
    }edge[Maxm];
    void init()
    {
        memset(vi,0,sizeof(vi));
        memset(head,-1,sizeof(head));
        memset(dfn,0,sizeof(dfn));
        memset(low,0,sizeof(low));
        lab=num=top=0;
        e=0;
    }
    void add(int u,int v)
    {
        edge[e].u=u,edge[e].v=v,edge[e].next=head[u],head[u]=e++;
    }
    double Dis(Point a,Point b)
    {
        return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));
    }
    void Tarjan(int u)
    {
        int i,j,v;
        dfn[u]=low[u]=++lab;
        Stack[top++]=u;
        vi[u]=1;
        for(i=head[u];i!=-1;i=edge[i].next)
        {
            v=edge[i].v;
            if(!dfn[v])
            {
                Tarjan(v);
                low[u]=min(low[u],low[v]);
            }
            if(vi[v])
                low[u]=min(low[u],dfn[v]);
        }
        if(low[u]==dfn[u])
        {
            ++num;
            do{
                i=Stack[--top];
                vi[i]=0;
                id[i]=num;
            }while(i!=u);
        }
    }
    int solve()
    {
        int i,j;
        for(i=1;i<=2*n;i++)
            if(!dfn[i])
            Tarjan(i);
        for(i=1;i<=n;i++)
            if(id[i]==id[i+n])
            return 0;
        return 1;
    }
    void buildGraphic(double mid)
    {
        init();
        int i,j;
        for(i=1;i<=n;i++)
        {
            for(j=i+1;j<=n;j++)
            {
                if(Dis(p[i],p[j])<mid)
                    add(i,j+n),add(j,i+n);
                if(Dis(p[i+n],p[j+n])<mid)
                    add(i+n,j),add(j+n,i);
            }
            for(j=1+n;j<=2*n;j++)
            {
                if(j==i+n) continue;
                if(Dis(p[i],p[j])<mid)
                    add(i,j-n),add(j,i+n);
            }
        }
    }
    int main()
    {
        int i,j;
        while(scanf("%d",&n)!=EOF)
        {
            init();
            for(i=1;i<=n;i++)
                scanf("%lf%lf%lf%lf",&p[i].x,&p[i].y,&p[i+n].x,&p[i+n].y);
            double l,r,mid;
            l=0,r=40000;
            while(l+eps<r)
            {
                mid=(l+r)/2;
                buildGraphic(mid*2);
                if(solve())
                    l=mid;
                else
                    r=mid;
            }
            printf("%.2lf
    ",l);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/wangfang20/p/3234618.html
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