zoukankan      html  css  js  c++  java
  • hdu 1164 Eddy's research I

    Problem Description
    Eddy's interest is very extensive, recently he is interested in prime number. Eddy discover the all number owned can be divided into the multiply of prime number, but he can't write program, so Eddy has to ask intelligent you to help him, he asks you to write a program which can do the number to divided into the multiply of prime number factor .

     
    Input
    The input will contain a number 1 < x<= 65535 per line representing the number of elements of the set.
     
    Output
    You have to print a line in the output for each entry with the answer to the previous question.
     
    Sample Input
    11 9412
     
    Sample Output
    11 2*2*13*181
     
    Author
    eddy
     
    Recommend
    JGShining   |   We have carefully selected several similar problems for you:  1215 1286 1211 1299 1163 
     
     
     1 #include <stdio.h>
     2 #include <math.h>
     3 #include <queue>
     4 #include <vector>
     5 #include <stack>
     6 #include <map>
     7 #include <string>
     8 #include <cstring>
     9 #include <algorithm>
    10 #include <iostream>
    11 using namespace std;
    12 int main()
    13 {
    14     int n,j,i,a[100];
    15     while(~scanf("%d",&n)){
    16         i=2;
    17         j=0;
    18         while(i<=n){
    19             if(n%i==0){
    20                 n/=i;
    21                 a[j++]=i;
    22                 i=2;
    23             }
    24             else{
    25                 i++;
    26             }
    27         }
    28         for(int m=0;m<j;m++){
    29             if(m==j-1){
    30                 printf("%d
    ",a[m]);
    31             }
    32             else{
    33                 printf("%d*", a[m]);
    34             }
    35         }
    36     }
    37     return 0;
    38 }
  • 相关阅读:
    Java异常面试题
    Quickhit快速击键
    多态and接口
    Java面向对象编程概述
    学生管理系统--分层开发
    类型转换
    文件上传
    ongl(示例3-6 多值类型的数据处理)
    ongl(原始类型和包装类型)
    Interceptor
  • 原文地址:https://www.cnblogs.com/wangmengmeng/p/4701728.html
Copyright © 2011-2022 走看看