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  • LeetCode83 Remove Duplicates from Sorted List

    题目:

    Given a sorted linked list, delete all duplicates such that each element appear only once. (Easy)

    For example,
    Given 1->1->2, return 1->2.
    Given 1->1->2->3->3, return 1->2->3.

    分析:

    链表去重。还是链表题的主要特点就是考察代码实现,除了个别题,没太多算法。

    代码:

     1 /**
     2  * Definition for singly-linked list.
     3  * struct ListNode {
     4  *     int val;
     5  *     ListNode *next;
     6  *     ListNode(int x) : val(x), next(NULL) {}
     7  * };
     8  */
     9 class Solution {
    10 public:
    11     ListNode* deleteDuplicates(ListNode* head) {
    12         ListNode dummy(0);
    13         dummy.next = head;
    14         while (head != nullptr && head -> next != nullptr) {
    15             if (head -> next -> val == head -> val) {
    16                 ListNode* temp = head -> next;
    17                 head -> next = head -> next -> next;
    18                 delete temp;
    19             }
    20             else {
    21                 head = head -> next;
    22             }
    23         }
    24         return dummy.next;
    25     }
    26 };
     
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  • 原文地址:https://www.cnblogs.com/wangxiaobao/p/5940217.html
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