zoukankan      html  css  js  c++  java
  • LeetCode121 Best Time to Buy and Sell Stock

    Say you have an array for which the ith element is the price of a given stock on day i. (Easy)

    Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).

    分析:

    一次遍历,维护之前的最小值即可。

    代码:

     1 class Solution {
     2 public:
     3     int maxProfit(vector<int>& prices) {
     4         if (prices.size() == 0) {
     5             return 0;
     6         }
     7         int minPrice = prices[0];
     8         int result = 0;
     9         for (int i = 1; i < prices.size(); ++i) {
    10             if (prices[i] < minPrice) {
    11                 minPrice = prices[i];
    12             }
    13             else if (prices[i] > minPrice) {
    14                 result = max(result,(prices[i] - minPrice));
    15             }
    16         }
    17         return result;
    18     }
    19 };
  • 相关阅读:
    react 采坑记录
    理解JS 模块化
    MongoDB使用教程
    scss
    gulp 使用教程
    node.js 简单入门
    jQuery
    jQuery
    php+mysql+bootstrap 实现成绩管理系统
    SVN的commit功能用bat实现
  • 原文地址:https://www.cnblogs.com/wangxiaobao/p/6095728.html
Copyright © 2011-2022 走看看