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  • poj2976 Dropping tests

    思路:

    二分最大化平均值,注意结果要四舍五入。

    实现:

     1 #include <cstdio>
     2 #include <algorithm>
     3 using namespace std;
     4 const int MAXN = 1005;
     5 const int INF = 0x3f3f3f3f;
     6 int a[MAXN], b[MAXN], n, k;
     7 double buf[MAXN];
     8 bool check(double m)
     9 {
    10     for (int i = 0; i < n; i++) buf[i] = a[i] - m * b[i];
    11     sort(buf, buf + n);
    12     double sum = 0;
    13     for (int i = n - 1; i >= k; i--)
    14         sum += buf[i];
    15     return sum >= 0;
    16 }
    17 int main()
    18 {
    19     while (scanf("%d %d", &n, &k), n || k)
    20     {
    21         for (int i = 0; i < n; i++)    scanf("%d", &a[i]);
    22         for (int i = 0; i < n; i++)    scanf("%d", &b[i]);
    23         double l = 0, r = 100, ans = 0;
    24         for (int i = 0; i < 100; i++)
    25         {
    26             double m = (l + r) / 2;
    27             if (check(m)) { ans = m; l = m; }
    28             else r = m;
    29         }
    30         printf("%d
    ", (int)(ans * 100 + 0.5));
    31     }
    32     return 0;
    33 }
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  • 原文地址:https://www.cnblogs.com/wangyiming/p/8359424.html
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