Binary String Matching http://acm.nyist.net/JudgeOnline/problem.php?pid=5

 

Binary String Matching

时间限制：3000 ms  |  内存限制：65535 KB

难度：3

 

描述

Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit

 

输入

The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.

输出

For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.

样例输入

3
11
1001110110
101
110010010010001
1010
110100010101011 

样例输出

3
0
3 

来源

网络

#include<stdio.h>
#include<string.h>
int main()
{
    int n;
    scanf("%d",&n);
    while(n--)
    {
         char a[15];
         char b[1010];
         int i,j,la,lb,p,count=0;
         scanf("%s",a);
         scanf("%s",b);
         la=strlen(a);
         lb=strlen(b);
         for(i=0;i<lb;i++)
         {
                p=1;
                if(a[0]==b[i])
                {
                    for(j=i;j<i+la;j++)
                    {
                          if(a[j-i]!=b[j])
                          {     
                                p=0;
                                break;
                           }
  
                     }
					if(p==1)
						count++;
                }
         }
         printf("%d
",count);
    }
    return 0;
}